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John begins running due north from point P1 at a speed of 2 meters per

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John begins running due north from point P1 at a speed of 2 meters per  [#permalink]

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New post 18 Sep 2018, 21:54
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John begins running due north from point P1 at a speed of 2 meters per second, while Peter starts running due south at the same moment from another point, P2 , at the same speed. What is the distance between Peter and John 5 seconds later?

(1) Point P1 is 10 meters due east of point P2.
(2) Peter is 40 meters due north of John after 10 seconds.

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John begins running due north from point P1 at a speed of 2 meters per  [#permalink]

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New post Updated on: 21 Sep 2018, 09:37
[Any suggestions why (2) is not enough? It suggests that both are on the same ax N-S and run toward each other.] solved

Originally posted by artiom01 on 21 Sep 2018, 05:50.
Last edited by artiom01 on 21 Sep 2018, 09:37, edited 1 time in total.
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Re: John begins running due north from point P1 at a speed of 2 meters per  [#permalink]

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New post 21 Sep 2018, 09:23
St 1: Distance between P1 and P2 on the straight line is given as 10m.
Now John traveled North up to point R. P1R = 10m.
Peter traveled same distance south. Name the point as S. P2S= 10m.
Join the points R&S and name the point as O where this line intersects line P1P2. We have two similar right angle triangles OP2S & OP1R.
P2S/P1R=OP2/OP1=OS/OR=1. OS and OR can be calculated easily and OS+OR = Distance between John and Peter. Sufficient.

St 2: After 10 seconds they will be separated by 40 meters as John traveled 20 m north and peter traveled 20m south but the distance between them varies as per the distance between points P1 and P2. Not Sufficient.

Answer:A
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Re: John begins running due north from point P1 at a speed of 2 meters per &nbs [#permalink] 21 Sep 2018, 09:23
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John begins running due north from point P1 at a speed of 2 meters per

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