Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
12 Mar 2017, 20:44
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
100% (05:21) correct
0%
(00:00)
wrong
based on 1
sessions
History
Date
Time
Result
Not Attempted Yet
John has 7 relatives, 3 men and 4 women. His wife Karen also has 7 relatives 3 women and 4 men. In how many ways can they invite 3 men and 3 women so that 3 of them are John's relatives and 3 his wife Karen's?
A. 485
B. 365
C. 458
D. 356
E. 285
A. 485
B. 365
C. 458
D. 356
E. 285
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
eddy8700
Joined: 25 Jan 2016
Last visit: 02 Oct 2020
Posts: 88
Own Kudos:
Given Kudos: 12
Status:active
Location: India
Concentration: Finance, Entrepreneurship
Schools: Rotman '19 Insead Sept'18 Booth '19
GPA: 4
WE:Web Development (Computer Software)
12 Mar 2017, 21:38
Kudos
Bookmarks
There are 4 cases:
John | Karen
relatives | relatives
Case invited | invited
----------------------------------
1. 3M, 0W | 0M, 3W
2. 2M, 1W | 1M, 2W
3. 1M, 2W | 2M, 1W
4. 0M, 3W | 3M, 0W
Case 1: Choose the John 3 men relatives 3C3 = 1 way.
Choose the Karen 3 women relatives 3C3=1 ways.
That's 1*1 = 1 way for Case 1.
Case 2: Choose the John 2 men relatives 3C2 = 3 ways.
Choose the Karen 1 woman relative 4C1 = 4 ways.
Choose the Karen 1 man relative 4C1=4 ways.
Choose the Karen 2 women relatives 3C2 = 3 ways.
That's 3*4*4*3 = 144 ways for Case 2.
Case 3: Choose the John 1 man relative 3C1 = 3 ways.
Choose the John 2 women relatives 4C2 = 6 ways.
Choose the Karen 2 men relative 4C2 = 6 ways.
Choose the Karen 1 woman relative 3C1 = 3 ways.
That's 3*6*6*3 = 324 ways for Case 3.
Case 4: Choose the John 3 women relatives 4C3 = 4 ways.
Choose the Karen 3 men relatives 4C3=4 way.
That's 4*4 = 16 ways for Case 4.
Grand total from all cases: 1+144+324+16 = 485 ways.
John | Karen
relatives | relatives
Case invited | invited
----------------------------------
1. 3M, 0W | 0M, 3W
2. 2M, 1W | 1M, 2W
3. 1M, 2W | 2M, 1W
4. 0M, 3W | 3M, 0W
Case 1: Choose the John 3 men relatives 3C3 = 1 way.
Choose the Karen 3 women relatives 3C3=1 ways.
That's 1*1 = 1 way for Case 1.
Case 2: Choose the John 2 men relatives 3C2 = 3 ways.
Choose the Karen 1 woman relative 4C1 = 4 ways.
Choose the Karen 1 man relative 4C1=4 ways.
Choose the Karen 2 women relatives 3C2 = 3 ways.
That's 3*4*4*3 = 144 ways for Case 2.
Case 3: Choose the John 1 man relative 3C1 = 3 ways.
Choose the John 2 women relatives 4C2 = 6 ways.
Choose the Karen 2 men relative 4C2 = 6 ways.
Choose the Karen 1 woman relative 3C1 = 3 ways.
That's 3*6*6*3 = 324 ways for Case 3.
Case 4: Choose the John 3 women relatives 4C3 = 4 ways.
Choose the Karen 3 men relatives 4C3=4 way.
That's 4*4 = 16 ways for Case 4.
Grand total from all cases: 1+144+324+16 = 485 ways.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
