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Abhi077
Jon and his twin sister, together with their 3 younger brothers, are wrapping presents. Each of the younger brothers can wrap presents at \(\frac{1}{4}\) of the rate that Jon and their older sister can each wrap presents. If all 5 children wrap presents at the same time, in what fraction of the time that it would take Jon and his twin sister to wrap 10 presents together will all 5 children working together take to complete the task?

\(A)\frac{2}{11}\\
B)\frac{4}{11}\\
C)\frac{8}{11}\\
D)\frac{11}{8}\\
E)\frac{11}{2}\)
Let´s say Jon (J) is able to wrap 4 presents per minute, and the same is valid for his twin sister (T).

Hence each younger brother (Y) can wrap 1 present per minute.

\(? = \frac{{{\text{Time}}\left( {J \cup T \cup 3Y} \right)}}{{\,{\text{Time}}\left( {J \cup T} \right)\,}}\)

During 1 min: J and T can wrap 8 presents, the whole group (J, T and 3Y) can wrap 11 presents.

The ratio (11/8) is the rate of jobs [per any interval of time] of (J, T and 3Y united) to (J and T united).

Our FOCUS, i.e., the rate of time [per any given job] of (J, T and 3Y united) to (J and T united) is its reciprocal:

\(? = \frac{{{\text{Time}}\left( {J \cup T \cup 3Y} \right)}}{{\,{\text{Time}}\left( {J \cup T} \right)\,}} = \frac{8}{{\,11\,}}\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.

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