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Jon’s cat consumes an average of 2.5 lbs of food per day

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Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 25 Apr 2017, 07:32
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Difficulty:

  35% (medium)

Question Stats:

72% (01:37) correct 28% (01:30) wrong based on 65 sessions

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Jon’s cat consumes an average of 2.5 lbs of food per day. Yesterday, the cat ate only .5 lbs of food. Approximately what percent of the average weekly food did the cat eat yesterday?

(A) 28%
(B) 2.8%
(C) 2%
(D) .28%
(E) .028%
Spoiler: OA

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Re: Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 25 Apr 2017, 10:07
Average Weekly Food = 2.5 lbsx7 days = 17.5 lbs
Yesterday 0.5 lbs.

Therefore % = 0.5/17.5 x 100 = 2.8 %

Ans (B)
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Re: Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 25 Apr 2017, 17:06
1
Average Weekly food = 2.5*7
% =\(\frac{0.5}{2.5*7}\)* 100
=\(\frac{1}{(5*7)}\)* 100
= \(\frac{20}{7}\) = 2.8 %
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Re: Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 26 Apr 2017, 01:36
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rohan2345 wrote:
Jon’s cat consumes an average of 2.5 lbs of food per day. Yesterday, the cat ate only .5 lbs of food. Approximately what percent of the average weekly food did the cat eat yesterday?

(A) 28%
(B) 2.8%
(C) 2%
(D) .28%
(E) .028%


Hey,

    • Daily consumption of cat \(= 2.5\) lbs
    • Therefore, total consumption in a week \(= (2.5 * 7)\) lbs
    • Yesterday’s consumption \(= 0.5\) lbs
      o Percentage of average weekly consumption yesterday was \(= \frac{(0.5*100)}{(2.5 * 7)} = \frac{20}{7} = 2.84\)%
    • Hence, the correct answer is Option B.


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Re: Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 29 Apr 2017, 08:58
rohan2345 wrote:
Jon’s cat consumes an average of 2.5 lbs of food per day. Yesterday, the cat ate only .5 lbs of food. Approximately what percent of the average weekly food did the cat eat yesterday?

(A) 28%
(B) 2.8%
(C) 2%
(D) .28%
(E) .028%


We are given that Jon’s cat consumes an average of 2.5 lbs of food per day, which means it eats 7 x 2.5 = 17.5 pounds of food per week.

Since yesterday the cat ate only 0.5 lbs of food, it consumed 0.5/17.5 = 5/175 = 1/35 x 100 = 2.8% of its average weekly food.

Answer: B
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Jon’s cat consumes an average of 2.5 lbs of food per day  [#permalink]

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New post 06 Apr 2019, 05:50
rohan2345 wrote:
Jon’s cat consumes an average of 2.5 lbs of food per day. Yesterday, the cat ate only .5 lbs of food. Approximately what percent of the average weekly food did the cat eat yesterday?

(A) 28%
(B) 2.8%
(C) 2%
(D) .28%
(E) .028%



When we are multiplying 2.5 with 7, isn't the result 17.5 the total weekly food consumption of the cat. Since the question asks for percent of the average weekly food, shouldn't we be dividing 0.5 by 2.5 multiplied by 100 to get the percentage.
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Jon’s cat consumes an average of 2.5 lbs of food per day   [#permalink] 06 Apr 2019, 05:50
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