targetgmatchotu wrote:
Hi folks,
I solved this problem. However, I am not able to get where I messed up such that I am unable to reach to the solution.
J1: 5:7
J2: 7:2
J3: 3:4 (J1+J2)
Let us take x from J1 and y from J2
Water from X: 5x
Water from Y: 7y
Orange from X: 7x
Orange from Y: 2y
Given in the question is that in what ratio J1+J2 such that J3: 3:4 Implies we have to calculate x:y
=> (5x+7y)/(7x+2y) = 3/4
=> (5 (x/y) + 7)/( 7 (x/y) +2) = 3/4
=> ( 5A + 7 ) / (7A +2 ) = 3/4
=> A=22
=> (x/y) = 22
Please advice where I am committing mistake.
Thanks in advance
Rgds,
TGC !!
You need to understand what you are doing. What do you mean by 'take x from J1'? What is x? Volume in lts? Fraction of total mixture? Think about it.
Say it is volume in lts.
Then
Water from X: 5x/12 lts
Water from Y: 7y/9 lts
Orange from X: 7x/12 lts
Orange from Y: 2y/9 lts
Given that water:orange in J3 is 3:4, we get amount of water in J3 is 3(x + y)/7 lts
Amount of orange in J3 = 4(x+y)/7 lts
We get
(5x/12 + 7y/9)/(7x/12 + 2y/9) = 3/4
(45x + 84y)/(63x + 24y) = 3/4
180x + 336y = 189x + 72y
9x = 264y
x/y = 88/3
But this is an extremely convoluted way of solving this question. Check out the methods given above.
I think you didn't get my query. My query is what is the issue with my solutions , and I am not asking alternative solutions which by basics is my last plan.