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28 Apr 2026, 20:19
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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June has \(x\) dollars saved for a trip and none for tuition. Starting now, for every dollar she saves for the trip, she saves \(m\) dollars for tuition. When the total amount she has saved for tuition equals the total amount she has saved for the trip, how much money will she have saved for the trip?
A. \(\frac{x}{m - 1}\)
B. \(\frac{xm}{m - 1}\)
C. \(\frac{x(m - 1)}{m}\)
D. \(\frac{xm}{m + 1}\)
E. \(x(m + 1)\)
A. \(\frac{x}{m - 1}\)
B. \(\frac{xm}{m - 1}\)
C. \(\frac{x(m - 1)}{m}\)
D. \(\frac{xm}{m + 1}\)
E. \(x(m + 1)\)
28 Apr 2026, 22:02
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Did it this way:
Initially, trip = x
Tuition = 0
From now on, for every 1 dollar in trip → m dollars in tuition
Let extra trip saving = a
So,
Trip = x + a
Tuition = m·a
When both become equal:
m·a = x + a
⇒ a(m − 1) = x
⇒ a = x/(m − 1)
Total trip = x + a
= x + x/(m − 1)
= xm/(m − 1)
Answer: xm/(m − 1)
If anything feels unclear, feel free to tag me — we can go through it.
– Rajdeep
Initially, trip = x
Tuition = 0
From now on, for every 1 dollar in trip → m dollars in tuition
Let extra trip saving = a
So,
Trip = x + a
Tuition = m·a
When both become equal:
m·a = x + a
⇒ a(m − 1) = x
⇒ a = x/(m − 1)
Total trip = x + a
= x + x/(m − 1)
= xm/(m − 1)
Answer: xm/(m − 1)
If anything feels unclear, feel free to tag me — we can go through it.
– Rajdeep
28 Apr 2026, 22:21
Kudos
Bookmarks
We have x dollars initially saved up.
Now we have 1:m ratio meaning for every 1 dollar, m dollars saved toward tuition.
Lets take it as:
y:my
The stem says:
x+y = my.
y = -x/(1-m)
Now total money for trip = x+y
= -x/(1-m) + x
= xm/(m-1)
Answer: Option B
Now we have 1:m ratio meaning for every 1 dollar, m dollars saved toward tuition.
Lets take it as:
y:my
The stem says:
x+y = my.
y = -x/(1-m)
Now total money for trip = x+y
= -x/(1-m) + x
= xm/(m-1)
Answer: Option B
kevincan
