K = wxyz, where w, x, y, z are prime numbers. Not including 1 and K

I assume it's \(K=w*x*y*z\), where w, x, y, z are prime numbers.

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

So if \(K=w^1*x^1*y^1*z^1\), where w, x, y, z are prime numbers then number of factors of K including 1 and K itself would be \((1+1)(1+1)(1+1)(1+1)=16\) and excluding 1 and K: \(16-2=14\).

For more on this check Number Theory chapter of Math Book: math-number-theory-88376.html

Hope it helps.