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Bunuel
Larry can build a model car in 3 hours, Moe can build the same car in 4 hours, and Fred can build the car in 5 hours. If the two fastest boys work together, how much of the car can they build in one hour?

A. 1/12
B. 2/7
C. 7/12
D. 8/15
E. 9/20


Lets say the car has 60 parts (lcm of 3, 4 and 5) in all ….
L can do 60 parts in 3 hrs means 20 parts / hr
Similarly, M can do 15 parts / hr
And F can do 12 parts / hr…

So the L + M (the fastest boys working together) can do 20 + 15 = 35 parts in an hour ..
So 35/60 = 7/12 in an hr …

Hit a Kudo if you like the approach :wink:
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Bunuel
Larry can build a model car in 3 hours, Moe can build the same car in 4 hours, and Fred can build the car in 5 hours. If the two fastest boys work together, how much of the car can they build in one hour?

A. 1/12
B. 2/7
C. 7/12
D. 8/15
E. 9/20

Let the total work be 60

Efficiency of Larry is 20
Efficiency of Moe is 15
Efficiency of Fred is 12

The 2 fastest boys in terms of efficiencies are - Larry & Moe, and their combined efficiencies are 35.

So, part of the car build in 1 hour is \(\frac{35}{60}\) => \(\frac{7}{12}\)

Thus, in 1 hour , (C) \(\frac{7}{12}\) part of the car is built...
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Larry and Moe are the fastest boys.

Therefore,

1/3 + 1/4
4/12 + 3/12
7/12

Which is answer C
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Bunuel
Larry can build a model car in 3 hours, Moe can build the same car in 4 hours, and Fred can build the car in 5 hours. If the two fastest boys work together, how much of the car can they build in one hour?

A. 1/12
B. 2/7
C. 7/12
D. 8/15
E. 9/20

Larry and Moe are the two fastest boys. Larry’s rate is 1 car in 3 hours, or 1/3 car per hour. Moe’s rate is 1 car in 4 hours, or 1/4 car per hour. Thus, in one hour, Larry and Moe can build 1/3 + 1/4 = 4/12 + 3/12 = 7/12 of a car.

Answer: C
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Bunuel
Larry can build a model car in 3 hours, Moe can build the same car in 4 hours, and Fred can build the car in 5 hours. If the two fastest boys work together, how much of the car can they build in one hour?

A. 1/12
B. 2/7
C. 7/12
D. 8/15
E. 9/20

Larry can build a model car in 3 hours, Moe can build the same car in 4 hours, and Fred can build the car in 5 hours.
So, from the above rule, we can conclude that:
Larry Rate 1/3
Moe Rate 1/4
Fred Rate 1/5

If the two fastest boys work together, how much of the car can they build in one hour?
Since Larry and Moe can each complete more of the job (than Fred can) in ONE HOUR, we know that Larry and Moe are the two fastest boys
In ONE HOUR Larry completes 1/3 of the job
In ONE HOUR Moe completes 1/4 of the job
So, working together, they can complete (1/3 + 1/4 ) of the job
1/3 + 1/4 = 4/12 + 3/12 = 7/12 ( Combined Rate )

Target Question how much of the car can they build in one hour?

Output in I hour = Time*Rate = 1* 7/12 = 7/12 (C )
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Hello from the GMAT Club BumpBot!

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