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Re: Larry has 14000 dollars to make two one-year investments, one of which [#permalink]
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solve it
(14000-x) * 6*1 = 3x
x = 93333
6% amount ; 14000-9333 ; 4666
option A

Afroditee wrote:
Larry has 14000 dollars to make two one-year investments, one of which has a simple annual interest rate of 6%, and the other has 3%. The interest of the two investment is the same. How much money is invested in the 6% investment?

A.4666.67

B.4560.12

C.6666

D.6667

E.6668
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Larry has 14000 dollars to make two one-year investments, one of which [#permalink]
1
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Let the first amount invested be x,
let the second amount invested be 14000-x.

Therefore, as we know the interest is the same for the amounts despite being invested at different interest rates.

\(\frac{x*6*1}{100}\) = \(\frac{14000-x*3*1}{100}\)

On further solving, x is 4666.67

The OA is A.
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Re: Larry has 14000 dollars to make two one-year investments, one of which [#permalink]
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Re: Larry has 14000 dollars to make two one-year investments, one of which [#permalink]
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