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12 Aug 2025, 22:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (01:41) correct
28%
(01:29)
wrong
based on 80
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Not Attempted Yet
Last summer in Munich it rained on each of the first 12 days of the World Cup. If it rained on 25 percent of the rest of the days of the World Cup, how many days was the competition?
(1) It rained on exactly fifty percent of all the days of the entire competition.
(2) It rained during the rest of the competition for half the number of days it rained in the first 12 days of the competition.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) It rained on exactly fifty percent of all the days of the entire competition.
(2) It rained during the rest of the competition for half the number of days it rained in the first 12 days of the competition.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
12 Aug 2025, 22:09
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Answer should be D
A - (12 + X/4) / (12 + X ) = 0.5
We get that x = 24 so total no of matches = 12 +24 = 36
B - no of days rained after first 12 days = 6 which is 25 %
Hence 24 days are played after first 12 days making total 36 days
Hence both are indiviually able to get the answers hence D.
A - (12 + X/4) / (12 + X ) = 0.5
We get that x = 24 so total no of matches = 12 +24 = 36
B - no of days rained after first 12 days = 6 which is 25 %
Hence 24 days are played after first 12 days making total 36 days
Hence both are indiviually able to get the answers hence D.
13 Aug 2025, 18:50
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okay let total days be X
we know it rained for 12
Now we have to find out of x days .also we know for how many days it rained of the remaining days ie 1/4(x-12)
Option 1
50% of all days it rained
x/2 days it rained
12 +1/4(x-12)=x/2
this is solvable (hence sufficient)
Option 2:
so it says in remaining days it rained for exactly half of what it had rained on first 12 days ie 6 days then
Now, we know that it rained for 25% of days of remaining days after first 12 days
So , we can say 1/4(x-12)=6 hence x is solvable from here.
It should then be option D
we know it rained for 12
Now we have to find out of x days .also we know for how many days it rained of the remaining days ie 1/4(x-12)
Option 1
50% of all days it rained
x/2 days it rained
12 +1/4(x-12)=x/2
this is solvable (hence sufficient)
Option 2:
so it says in remaining days it rained for exactly half of what it had rained on first 12 days ie 6 days then
Now, we know that it rained for 25% of days of remaining days after first 12 days
So , we can say 1/4(x-12)=6 hence x is solvable from here.
It should then be option D
Bunuel
