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06 Jan 2021, 04:24
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D
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Difficulty:
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Question Stats:
84% (02:25) correct
16%
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based on 102
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Lauren drove to work in the morning at an average speed of 60 miles per hour. Lauren’s return trip to home on the same route took 45 minutes longer than the morning trip. If Lauren averaged a speed of 45 miles per hour on her return trip, then how far does Lauren live from work?
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
06 Jan 2021, 05:54
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sjuniv32
Lauren drove to work in the morning at an average speed of 60 miles per hour. Lauren’s return trip to home on the same route took 45 minutes longer than the morning trip. If Lauren averaged a speed of 45 miles per hour on her return trip, then how far does Lauren live from work?
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
Distance travelled both sides is the same.
SpeedM : SpeedE = 60 : 45 = 4 : 3
TimeM : TimeE = 3:4
This difference of 1 is equal to 45 mins so time taken in morning is 3 * 45 = 135 mins
Distance from work = Speed * Time = 1 mile/min * 135 min = 135 miles
Answer (D)
For more on ratios, check:
Ratios Basics Video: https://youtu.be/5ODENGG5dvc
Ratios Basics Post: https://anaprep.com/arithmetic-ratios-t ... ll-starts/
TSD Video: https://youtu.be/7ASEIvxYPCM
General Discussion
06 Jan 2021, 04:48
Kudos
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sjuniv32
Lauren drove to work in the morning at an average speed of 60 miles per hour. Lauren’s return trip to home on the same route took 45 minutes longer than the morning trip. If Lauren averaged a speed of 45 miles per hour on her return trip, then how far does Lauren live from work?
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
(A) 75
(B) 90
(C) 120
(D) 135
(E) 150
Let the distance be d.
The time taken while going =\(\frac{ d}{60}\)
Time taken while coming back = \(\frac{d}{45}=\frac{d}{60} +\frac{45}{60}\)
So \(\frac{d}{45}=\frac{d}{60}+\frac{3}{4}\)
Multiply by 180
\(d*4=3*d+3*45.....d=135\)
D
Another version ( which I initially thought it to be)
Quote:
Lauren drove to work in the morning at an average speed of 60 miles per hour. Lauren’s return trip to home on the same route took 45 minutes longer than the morning trip. If Lauren averaged a speed of 45 miles per hour on her return entire trip, then how far does Lauren live from work?
Let the distance be d. The time taken while going = \(\frac{d}{60}\)
Time taken while coming back = \(\frac{d}{60} +\frac{45}{60}\)
Time taken for entire trip at the rate of 45 miles per hour = \(\frac{2d}{45}\)
So \(\frac{d}{60}+\frac{d}{60}+\frac{3}{4}=\frac{2d}{45}\)
Multiply by 180
\(2d*3+45*3=2d*4\)
\(2d=135\)
So total distance is 135, but the distance one way is 135/2.
