Let a, b, c, d, and e represent positive integers. Is |ab + c| = cd -

#1
√≠cd−e(cd−e)2≠cd−e
l(cd-e)l≠ cd-e
or say
lab+cl≠lcd+el
sufficient
#2
|e|>|cd|
in that case
|ab+c|=cd−e
LHS will be -ve always
so |ab+c|=cd−e not true
IMO D

Let a, b, c, d, and e represent positive integers. Is |ab+c|=cd−e?

(1) (cd−e)2‾‾‾‾‾‾‾‾‾√≠cd−e(cd−e)2≠cd−e

(2) |e|>|cd|

We know that a,b,c,d, and e are positive integers. We are to determine if |ab+c|=cd-e.
What is worth noting is that, |ab+c| is a positive number. All that we need in order to make a decision is to determine that cd-e is negative. Once we are able to establish that, we can conclude that |ab+c|≠cd-e.

Statement 1: √{(cd-e)^2}≠cd-e.
we don't know if cd>e or e>cd, so we cannot be able to determine if cd-e is negative or positive. If it is negative, we know |ab+c| cannot equal cd-e, but if cd-e is positive, there is a possibility that |ab+c| is equal to cd-e. Statement 1 is therefore insufficient.

Statement 2: |e|>|cd|
This means that e-cd is positive, and by extension, cd-e is negative. This is sufficient since we know that definitely |ab+c| can never equal cd-e. Since we know a,b, and c are all positive numbers, so ab+c will result in a positive number and an absolute value of a positive number cannot be negative.

Statement 2 alone is sufficient.

The answer is B.

(a,b,c,d,e)>0

|ab+c|≥0…cd−e≥0…cd≥e?

(1) \(\sqrt{(cd−e)^2}≠cd−e\) sufic

if (cd-e)≥0, cd≥e;
if (cd-e)<0, cd<e;

|cd-e|=cd-e when cd≥e;
|cd-e|≠cd-e when cd<e;

(2) |e|>|cd| sufic

\(|e|>|cd|…e>cd\)

Ans (D)

Q. Is \(|ab+c|=cd−e\)?
Since the output of absolute value is always zero or positive, this question actually asks whether \(cd-e \geq{0}\)

(1) \(\sqrt{(cd−e)^2}≠cd−e\)
This statement can be rewritten as \(|cd−e|≠cd−e\), meaning that \(cd−e <0\) as the output of absolute value is always zero or positive.
This exactly answers the question above.
SUFFICIENT

(2) |e|>|cd|
If \(cd\) is positive and \(e\) is positive, then \(cd−e<0\) and this answers the question above.
SUFFICIENT

Answer is (D)

For cd-e to be equal to an absolute value, cd must be greater than or equal to e.

Both statements states that cd is smaller than e. Hence, ans to the question is no and each statement is sufficient.

IMO, Ans D

Posted from my mobile device

Let a, b, c, d, and e represent positive integers. Is |ab+c|=cd−e ?
--> cd-e ≥0 --> \(cd ≥e ?\)

(Statement1): \(\sqrt{(cd-e)}^{2} ≠ cd-e\)
-->\( \sqrt{(cd-e)}^{2} = |cd -e|\)

if \(\sqrt{(cd-e)}^{2} ≠ cd-e\), then
-->\( \sqrt{(cd-e)}^{2} = -( cd-e)= e- cd\)

that means that e is greater than cd \((e > cd)\)
--> Always NO
sufficient

(Statement2): \(|e| > |cd|\)
(Squaring both sides )--> \(e^{2} > cd^{2}\)
\(e^{2} -cd^{2} >0\)
\((e -cd)(e+ cd) >0\)

NO info about whether e is greater than cd.
Insufficient

The answer is A.

I feel the answer is D

As e, c & d are positive integers,
If |e| > |cd|
It will only imply e > cd, the other solution e<-cd is not possible as all of them are given as positive

Bunuel chetan2u
Pls clarify.

Posted from my mobile device

Yes you are correct.
Since e and both c and d are positive.
|e|=e and |cd|=cd
This |e|>|cd| means e>cd
And this too is sufficient.

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