|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
18 Mar 2022, 07:15
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (02:21) correct
25%
(02:41)
wrong
based on 101
sessions
History
Date
Time
Result
Not Attempted Yet
Let \(M = 10!\) and let \(N = M^3\). If a is the greatest integer value of x such that \(2^x\) is a factor of N, and b is the greatest integer value of y such that \(3^y\) is a factor of N, then what is the value of a + b?
A. 18
B. 24
C. 33
D. 36
E. 54
Are You Up For the Challenge: 700 Level Questions
A. 18
B. 24
C. 33
D. 36
E. 54
Are You Up For the Challenge: 700 Level Questions
20 Mar 2022, 22:44
Kudos
Bookmarks
Bunuel
a is the greatest integer value of x such that \(2^x\) is a factor of N or \((10!)^3\)
Max value of x in 10! = \(\frac{10}{2}+\frac{10}{2^2}+\frac{10}{2^3} = 5+2+1=8\) { Add the integer part of each fraction}
Thus, Max value of x in N or \(10!^3\) = 8*3 = a { DO not take 8^3, because it will be 8+8+8, as the power of 2 gets added up}
Similarly for b,
b is the greatest integer value of y such that \(3^y\) is a factor of N or \((10!)^3\)
Max value of y in 10! = \(\frac{10}{3}+\frac{10}{3^2}+\frac{10}{3^3} = 3+1=4\) { Add the integer part of each fraction}
Thus, Max value of y in N or \(10!^3\) = 4*3 = b
a+b = 24+12 =36
D
21 Mar 2023, 22:13
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
