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Joined: 02 Sep 2009
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Let m, n and k be digits, where m + n = k. What is k?
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15 Dec 2016, 04:44
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53% (00:59) correct 47% (00:59) wrong based on 138 sessions
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Let m, n and k be digits, where m + n = k. What is k? (1) m = 4 (2) n > m
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Re: Let m, n and k be digits, where m + n = k. What is k?
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15 Dec 2016, 05:19
Bunuel wrote: Let m, n and k be digits, where m + n = k. What is k?
(1) m = 4 (2) n > m We have set of digits to choose from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}\(m + n = k\) (1) \(m=4\) It can be \((4 + 0), (4 + 1), (4 + 2)\) ... till \((4 + 5)\) Insufficient (2) \(n > m\) Again it can be \((0 + 1), (1 + 5)\) etc. Clearly insufficient. (1) & (2) together: If \(m = 4\) and \(n > m\) than only option awailable for n can me 5. And our k = 4 + 5 = 9 Sufficient. Answer C



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Re: Let m, n and k be digits, where m + n = k. What is k?
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15 Dec 2016, 06:05
Option C)Given: m, n & k are all digits "or" Simplifying  m, n & k can have any possible value from set [0,9]. Also, m + n = k; k = ? I: m = 4 : 4 + n = k; as 0 <= n <= 9 :for n = 0, k = 4 :n= 1, k =5 : ... multiple values possible Insufficient II: n > m : m + n = k :for m = 0; n = 1 or 2 or 3 or 4 or 5 or 6 . . . :m = 1; n = 2 or 3 or 4 or 5 or 6 . . . multiple values possible Insufficient I + II: :m = 4 and n > m : 4 < n <= 9 : k = m + n = 4 + n : for n = 5, k = 4 + 5 = 9 and being a digit, max. possible value k can take is 9. Sufficient.
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Re: Let m, n and k be digits, where m + n = k. What is k?
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02 May 2017, 15:35
Bunuel wrote: Let m, n and k be digits, where m + n = k. What is k?
(1) m = 4 (2) n > m since we speak about digits, the only value that m, n, and k can take are: 0 1 2 3 4 5 6 7 8 9 1. m=4. we don't know anything about n. if n=1 then k=5. if n=2, then k=6. not sufficient. 2. n>m. if m=1, then n can be anything from 2 to 8. if m=2, then n can be anything from 3 to 7. not sufficient. 1+2. m=4, and n>m. since k must be a digit, and since the maximum value n can take is 5, so as for k to be a digit itself and satisfy the condition, we know for sure that m=5, and k=9.



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Re: Let m, n and k be digits, where m + n = k. What is k?
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19 Feb 2019, 04:59
Bunuel wrote: Let m, n and k be digits, where m + n = k. What is k?
(1) m = 4 (2) n > m All m, n and k are digits Now m + n =k from 1, m= 4, n can be 1,2,3,4,5 for k to be 5,6,7,8,9 from 2, n>m, nothing is required Combination Only one value 4 + 5 = 9 C
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Re: Let m, n and k be digits, where m + n = k. What is k?
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19 Feb 2019, 04:59






