The question says that the
number of factors of \(5^{n}\) is 15 and not the number of 5’s
To calculate number of factors of any integer,
First make prime factorization of an integer \(k = a^{p} * b^{q} * c^{r}\), where a, b, and c are prime factors of k and p, q, and r are their powers.
The number of factors of k will be expressed by the formula (p+1)(q+1)(r+1).
Example: Finding the number of all factors of 450: \(2^{1} 3^{2} 5^{2}\)
Total number of factors of 450 including 1 and 450 itself is (1+1) * (2+1) * (2+1) = 18 factors.
In the given question k = \(5^{n}\) => we see 5 is already a prime number, for k to have 15 factors, n should be 14.
Mgerman42
why is n 14? 15 5's would be 5^15. Clearly I'm wrong but the three answers to these questions all just list the same info
chetan2u
mastergrinder
Let n be a positive integer such that the number of positive factors of \(5^n\) is 15. What is the number of positive factors of \(9^n\)?
A. 14
B. 15
C. 28
D. 29
E. 30
Number of positive factors of \(5^n\) is n+1 as ‘5’ is prime.
Thus, n+1=15 or n=14
Get \(9^n\) in prime factorisation => \(9^n=3^{2n}\)
Thus, number of positive factors = (2n+1) = 2*14+1 =29