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Let n be the largest integer that is the product of exactly 3 distinct

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Let n be the largest integer that is the product of exactly 3 distinct  [#permalink]

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New post 19 Mar 2019, 02:30
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A
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C
D
E

Difficulty:

  85% (hard)

Question Stats:

35% (02:20) correct 65% (02:55) wrong based on 31 sessions

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Let n be the largest integer that is the product of exactly 3 distinct  [#permalink]

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New post 19 Mar 2019, 04:42
Bunuel wrote:
Let n be the largest integer that is the product of exactly 3 distinct prime numbers d, e, and 10d + e, where d and e are single digits. What is the sum of the digits of n ?

(A) 12
(B) 15
(C) 18
(D) 21
(E) 24


Let me start this question by thinking the biggest two digit prime numbers (to find biggest possibility of 10d+e) whose both digits (d and e) are prime

The umber can't be in 90's or 80's as 8 and 9 are non-prime digits

so the number may be 73 where d = 7 and e = 3

i.e. n = 3*7*73 = 1533

Sum of digits of n = 1+5+3+3 = 12

Answer: Option A
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Re: Let n be the largest integer that is the product of exactly 3 distinct  [#permalink]

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New post 19 Mar 2019, 10:32
Bunuel wrote:
Let n be the largest integer that is the product of exactly 3 distinct prime numbers d, e, and 10d + e, where d and e are single digits. What is the sum of the digits of n ?

(A) 12
(B) 15
(C) 18
(D) 21
(E) 24


d,e, * 10d+3 are all prime no
so largest no which would be possible 7,3,73
product = 1533 ; sum of digits= 12
IMO A
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Re: Let n be the largest integer that is the product of exactly 3 distinct   [#permalink] 19 Mar 2019, 10:32
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