Look at the following image which shows the problem pictorially.
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Stmt 1: Let ∠ABE = ?, then ∠BEF = 3?. Since ∠BEF = 3?, ∠DEY = 3?, also as ∠ABE = ?, ∠CBE = 180-?. Since we can not assume line AC and DF to be parallel, we can't proceed from here to find any relation to find ∠CBE. Hence
insufficient.
Stmt 2: Let ∠ABX = 180-?, then ∠DEY = 180-? but again we need one more relation which can lock value of ?. This is same condition as in stmt 1 hence
insufficient.
Stmt 1 and Stmt 2: As explained above, now ∠ABE = ?, ∠ABX = 180-? and ∠CBE = 180-?. Since ∠BEF = 3?,
∠DEY = 3?. Now as per stmt 2, ∠ABX =
∠DEY = 180-?. So there are two values of ∠DEY, equate them and we can find value of ? and hence ∠CBE = 180-?. Hence
sufficient.
Therefore
C is the correct answer.rohitgm
Line AC is intersected by line XY at point B. Line DF is intersected by line XY at point E. What is the degree measure of angle CBE?
1. The degree measure of angle BEF is three times the degree measure of angle ABE.
2. The degree measure of angle ABX is equal to the degree measure of angle DEY.
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