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24 Mar 2020, 08:07
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:17) correct
25%
(01:14)
wrong
based on 186
sessions
History
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Not Attempted Yet
Line \(l_1\) is given by the equation \(y = mx + 3\), and line \(l_2\) is given by the equation \(y = nx − 7\), where m and n are constants. Is \(l_1\) parallel to \(l_2\) ?
(1) \(m^2 − n^2 = 0\)
(2) \(mn\) is positive.
(1) \(m^2 − n^2 = 0\)
(2) \(mn\) is positive.
24 Mar 2020, 09:47
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Bunuel
Line \(l_1\) is given by the equation \(y = mx + 3\), and line \(l_2\) is given by the equation \(y = nx − 7\), where m and n are constants. Is \(l_1\) parallel to \(l_2\) ?
1) \(m^2 − n^2 = 0\)
(2) \(mn\) is positive.
1) \(m^2 − n^2 = 0\)
(2) \(mn\) is positive.
Is m=n?
(1) \(m^2 − n^2 = 0\)
|m| = |n|
But m = -n is a possibility
m = n is also a possibility
NOT SUFFICIENT
(2) \(mn\) is positive.
m & n are either both +ve or both -ve
NOT SUFFICIENT
(1) + (2)
(1) \(m^2 − n^2 = 0\)
|m| = |n|
But m = -n is a possibility
m = n is also a possibility
(2) \(mn\) is positive.[/quote]
m & n are either both +ve or both -ve
m = n is the only possibility since m = -n is not possible
SUFFICIENT
IMO C
09 Jan 2024, 18:02
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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