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Line r passes through points A (-3, 2) and B (0, 0). Which of the following represents a line that is perpendicular to line r?

There is no need to calculate the st. line perpendicular to st. line r

Slope of r = \(\frac{2}{-3}\) = \(\frac{-2}{3}\)

Slope of perpendicular =\( \frac{3}{2} \)= \(\frac{-coeff of x }{coeff of y}\) . It satisfies only E. :)
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Line r passes through points A (-3, 2) and B (0, 0): Slope : \(\frac{-2}{3 }\)

A line that is perpendicular to line 'r' will have a slope negative reciprocal of \(\frac{-2}{3 }\) which is \(\frac{3}{2 }\).

Check options for slope after rearranging the equation in the standard form of y = mx + c

A: Negative slope - OUT

B: Negative slope - OUT

C: \(\frac{-2}{3 }\) - Negative slope - OUT

D: \(\frac{-3}{2 }\) - Negative slope - OUT

E: \(\frac{3}{2 }\) - Answer

Answer E
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