vivektripathi wrote:

List A contains x1,x2,...., x10; list B contains y1, y2, ...y10, where numbers in B are the remainders when the numbers in A is divided by 2, respectively. What is sum of numbers in B?

1). Sum of numbers in A is 100

2). There are 6 even numbers in B

IMO "B"....

First, let's put an assumption that the numbers are integers.

From the second stem, we can get the sum of numbers in B, which is 4 since the remainders of the 4 odd numbers are 1.

SO, it's sufficient.

Now for the 1st stem, if that is sufficient we get D for answer, if not, B for answer.

Sum of ten integers equal to 100. Let's say 9 integers are 0, and last number is 100. Then sum of B is 0.

If, 8 numbers are 0 and 2 are not, namely, 3 and 97. Then we get 2 for sum of B.

If, the remaining 2 numbers are even, then the sum of B is 0.

I think the answer is B.