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C
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Difficulty:
55%
(hard)
Question Stats:
67% (02:00) correct
33%
(02:40)
wrong
based on 102
sessions
History
Date
Time
Result
Not Attempted Yet
Luca, working at a constant rate, can complete a data migration working alone in 24 days, while Marco, working at a constant rate, can complete the same migration working alone in twice that time. They start working together, but Luca stops working 6 days before the migration is finished. How many total days does it take to finish the migration under this schedule?
A. 16 days
B. 18 days
C. 20 days
D. 24 days
E. 30 days
A. 16 days
B. 18 days
C. 20 days
D. 24 days
E. 30 days
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M47-08
10 Feb 2026, 09:45
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Bunuel
GMAT Club Official Solution:
Let total time = T
Luca rate = 1/24
Marco rate = 1/48
Luca works T - 6 days
Marco works T days
Thus:
(T - 6)* 1/24 + T * 1/48 = 1
T = 20
Answer: C.
General Discussion
02 Feb 2026, 08:54
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Bookmarks
Luca's rate is \(\frac{1}{24}\) per day,
and Marco's rate is \(\frac{1}{48 }\) per day.
Let T be the total days to finish the migration.
Luca works for T−6 days, while Marco works all T days.
Their combined work is: \(\frac{T − 6}{24}\) + \(\frac{1}{48 }\) = 1
Using a common denominator of 48: \(\frac{2(T − 6)}{24}\) + \(\frac{1}{48 }\)
2T−12+T=48
3T−12=48
3T=60
T=20
ANS = C
and Marco's rate is \(\frac{1}{48 }\) per day.
Let T be the total days to finish the migration.
Luca works for T−6 days, while Marco works all T days.
Their combined work is: \(\frac{T − 6}{24}\) + \(\frac{1}{48 }\) = 1
Using a common denominator of 48: \(\frac{2(T − 6)}{24}\) + \(\frac{1}{48 }\)
2T−12+T=48
3T−12=48
3T=60
T=20
ANS = C
