It is currently 17 Mar 2018, 19:21

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M AND N.....................

Author Message
Manager
Joined: 02 Sep 2008
Posts: 103

### Show Tags

01 Apr 2009, 03:27
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:15) correct 0% (00:00) wrong based on 5 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
Director
Joined: 04 Jan 2008
Posts: 868

### Show Tags

01 Apr 2009, 04:02
Its A
remainder of M+N will be 4
_________________

http://gmatclub.com/forum/math-polygons-87336.html
http://gmatclub.com/forum/competition-for-the-best-gmat-error-log-template-86232.html

Intern
Joined: 09 Aug 2009
Posts: 4

### Show Tags

09 Aug 2009, 19:47
Could you please explain the solution? I seem to have major difficulties solving "remainder problems".
Intern
Joined: 09 Aug 2009
Posts: 4

### Show Tags

09 Aug 2009, 19:52
No need to explain... just figured it out myself. But thanks for posting the answer. Without it I could not have resolved it!
Retired Moderator
Joined: 05 Jul 2006
Posts: 1741

### Show Tags

09 Aug 2009, 22:13
milind1979 wrote:
. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10

m = 6x+1, n = 6y+3

6x+1+6y+3 = 6x+6y+4

A = 86 -4 = 82,82 is not devisible by 6

52 - 4 = 48....could be
34-4 = could be
28-4 = 24..could be

10-4 = 6 could be ( x or y = 0)

Manager
Joined: 28 Jul 2009
Posts: 119
Location: India
Schools: NUS, NTU, SMU, AGSM, Melbourne School of Business

### Show Tags

09 Aug 2009, 23:28
Try plugging in relatively easy numbers.
For M, plug 7(6+1). For N, plug 9(6+3).
Adding M+N, we get 16 (7+9).

Divide it with 6, and you get remainder 4.
Look for the options that don't give this remainder. Thats your Answer!
_________________

GMAT offended me. Now, its my turn!
Will do anything for Kudos! Please feel free to give one.

Re: M AND N.....................   [#permalink] 09 Aug 2009, 23:28
Display posts from previous: Sort by