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# M is the sum of three consecutive odd integers, the least of which is

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Math Expert
Joined: 02 Sep 2009
Posts: 58465
M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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03 Jul 2018, 01:18
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45% (medium)

Question Stats:

64% (01:52) correct 37% (02:02) wrong based on 200 sessions

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M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) $$M + 12$$

B) $$M + 6$$

C) $$M - 6$$

D) $$M - 12$$

E) $$\frac{M}{2}$$

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M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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Updated on: 04 Aug 2018, 09:32
1
Ans: D

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
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Originally posted by D3N0 on 03 Jul 2018, 01:33.
Last edited by D3N0 on 04 Aug 2018, 09:32, edited 2 times in total.
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Re: M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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03 Jul 2018, 03:01
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) $$M + 12$$

B) $$M + 6$$

C) $$M - 6$$

D) $$M - 12$$

E) $$\frac{M}{2}$$

M=t+t+2+t+4
M=3t+6
t=(M-6)/3
M2=t+t-2+t-4
M2=3t-6
M2=3(M-6)/3 -6
M2=M-6-6=M-12
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Re: M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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04 Aug 2018, 06:48
D3N0 wrote:
Ans: D

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= 3(M-6)/2 -6 = M-6-6 = M-12Ans: D

We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) $$M + 12$$

B) $$M + 6$$

C) $$M - 6$$

D) $$M - 12$$

E) $$\frac{M}{2}$$

hey there
what did you in highlighted part
thank you
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Re: M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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04 Aug 2018, 07:48
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) $$M + 12$$

B) $$M + 6$$

C) $$M - 6$$

D) $$M - 12$$

E) $$\frac{M}{2}$$

Plug in some numbers and check

Scene I

Let the 3 numbers be 5,7 &9 (Where t = 5)

SO, M = 21

Scene II

Let the 3 numbers be 1 , 3 & 5

SO, M = 9

Now, check ANswer must be 21 - 12 = 9, So, ANswer must be (D)
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Re: M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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27 Feb 2019, 23:53
1
HI Bunuel

Seems like this question is discussed in the below link

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

https://gmatclub.com/forum/m-is-the-sum ... fl=similar
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Posts: 58465
Re: M is the sum of three consecutive odd integers, the least of which is  [#permalink]

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27 Feb 2019, 23:56
NandishSS wrote:
HI Bunuel

Seems like this question is discussed in the below link

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

https://gmatclub.com/forum/m-is-the-sum ... fl=similar

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Fixed. Thank you.
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Re: M is the sum of three consecutive odd integers, the least of which is   [#permalink] 27 Feb 2019, 23:56
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