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03 Jul 2018, 01:18
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:57) correct
29%
(02:03)
wrong
based on 563
sessions
History
Date
Time
Result
Not Attempted Yet
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?
A) \(M + 12\)
B) \(M + 6\)
C) \(M - 6\)
D) \(M - 12\)
E) \(\frac{M}{2}\)
A) \(M + 12\)
B) \(M + 6\)
C) \(M - 6\)
D) \(M - 12\)
E) \(\frac{M}{2}\)
Ans: D
three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3
Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D
We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3
Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D
We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
03 Jul 2018, 03:01
Kudos
Bookmarks
Bunuel
M=t+t+2+t+4
M=3t+6
t=(M-6)/3
M2=t+t-2+t-4
M2=3t-6
M2=3(M-6)/3 -6
M2=M-6-6=M-12
