Ans: D
three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3
Now we need to find t+ t-2+t-4 = 3t -6
= 3(M-6)/2 -6 = M-6-6 = M-12Ans: D
We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?
A) \(M + 12\)
B) \(M + 6\)
C) \(M - 6\)
D) \(M - 12\)
E) \(\frac{M}{2}\)