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M is the sum of three consecutive odd integers, the least of which is

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Bunuel
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M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   03 Jul 2018, 01:18
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M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) \(M + 12\)

B) \(M + 6\)

C) \(M - 6\)

D) \(M - 12\)

E) \(\frac{M}{2}\)
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M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   Updated on: 04 Aug 2018, 09:32
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Ans: D

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.

Originally posted by D3N0 on 03 Jul 2018, 01:33.
Last edited by D3N0 on 04 Aug 2018, 09:32, edited 2 times in total.
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   03 Jul 2018, 03:01
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Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) \(M + 12\)

B) \(M + 6\)

C) \(M - 6\)

D) \(M - 12\)

E) \(\frac{M}{2}\)



M=t+t+2+t+4
M=3t+6
t=(M-6)/3
M2=t+t-2+t-4
M2=3t-6
M2=3(M-6)/3 -6
M2=M-6-6=M-12
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   04 Aug 2018, 06:48
D3N0 wrote:
Ans: D

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= 3(M-6)/2 -6 = M-6-6 = M-12Ans: D

We can also do this by putting values:
lets say t = 7 so M= 7+9+11 = 27
now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) \(M + 12\)

B) \(M + 6\)

C) \(M - 6\)

D) \(M - 12\)

E) \(\frac{M}{2}\)


hey there :-)
what did you in highlighted part :?
thank you :-)
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   04 Aug 2018, 07:48
Bunuel wrote:
M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) \(M + 12\)

B) \(M + 6\)

C) \(M - 6\)

D) \(M - 12\)

E) \(\frac{M}{2}\)


Plug in some numbers and check

Scene I

Let the 3 numbers be 5,7 &9 (Where t = 5)

SO, M = 21

Scene II

Let the 3 numbers be 1 , 3 & 5

SO, M = 9

Now, check ANswer must be 21 - 12 = 9, So, ANswer must be (D)
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NandishSS
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   27 Feb 2019, 23:53
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HI Bunuel

Seems like this question is discussed in the below link :-)

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

https://gmatclub.com/forum/m-is-the-sum ... fl=similar
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Bunuel
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   27 Feb 2019, 23:56
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NandishSS wrote:
HI Bunuel

Seems like this question is discussed in the below link :-)

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
= [3*(M-6)]/3 -6 = M-6-6 = M-12
Ans: D

https://gmatclub.com/forum/m-is-the-sum ... fl=similar

______________________
Fixed. Thank you.
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ShubhamDadhe
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink] New post   27 Oct 2023, 00:15
I have a doubt regarding the solution to this question:

I understood the below part:

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6

But from here on, how did we arrive at the below equation?

= 3(M-6)/2 -6 = M-6-6 = M-12Ans: D

Can somebody please explain this?
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Re: M is the sum of three consecutive odd integers, the least of which is [#permalink]
27 Oct 2023, 00:15
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