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M00-05

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M00-05  [#permalink]

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New post 16 Sep 2014, 00:14
1
6
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

57% (00:55) correct 43% (00:43) wrong based on 98 sessions

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Re M00-05  [#permalink]

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New post 16 Sep 2014, 00:14
Official Solution:


S1 states that \(z\) is one of the following: -75, 0, 75, 150, etc. It is not sufficient since when \(z=0\), the expression is an integer, in all other cases it is not. INSUFFICIENT.

S2 gives a range of numbers where again, the expression may or may not be an integer. INSUFFICIENT.

Combining both statements together, \(z\) can be 0 or 75. This is again INSUFFICIENT.


Answer: E
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Re: M00-05  [#permalink]

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New post 17 Jan 2015, 19:36
From statement 1 alone, can you conclude that the set is evenly spaced?
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New post 18 Jan 2015, 02:57
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New post 18 Jan 2015, 14:09
Bunuel wrote:
backthatassetup wrote:
From statement 1 alone, can you conclude that the set is evenly spaced?


We don't have a set there... -75, 0, 75, 150, .. are possible values of z.


Oops posted my question on the wrong page. Thanks for the response
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New post 17 Mar 2015, 05:10
of z can only take value of 0 or 75, 75/(z+1) will be always integer. Could you please explain if i am missing something?
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New post 17 Mar 2015, 05:30
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Re: M00-05  [#permalink]

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New post 17 Mar 2015, 06:49
Thank you. i missed that.
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New post 30 May 2016, 09:46
I think this is a high-quality question and I agree with explanation.
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Re: M00-05  [#permalink]

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New post 17 Jan 2017, 04:19
Combining 1 & 2 we are getting solution 0 and 75. In both these cases the expression 75/z+1 will not be an integer. So why Option C is wrong??
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New post 17 Jan 2017, 05:16
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Re: M00-05  [#permalink]

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New post 18 Jan 2017, 05:59
1
Is \(\frac{75}{z+1}\) an integer?


(1) \(z = 75x\) where \(x\) is an integer

Test Integer vlaue. ZERO is integer too.

Let x =0 ...........z=0 .........then 75/1 =75...Answer is YES

Let x =1 ...........z=75 .........then 75/76.......Answer is No

Insufficient

(2) \(0 \le z \le 75\)

Test the limits: 0 & 75.. . So the result will as statement 1.

Insufficient

Combining 1 & 2

Same testing values gives same answers.

Answer: E
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Re: M00-05  [#permalink]

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New post 14 Jul 2018, 03:05
I've spent almost one hour on this and I don't understand why the solution is not C.

From S(1)
Let x =0 ...........z=0 .........then 75/1 =75...Answer is YES
Let x =1 ...........z=75 .........then 75/76.......Answer is NO
Let x=3.....z=225...then 75/225 not integer answer is NO
And for the rest of x the answer is NO

From S(2), different
Let z=0......then 75/1=75 answer is YES
Let z=2.....then 75/3=25 answer is YES
Let z=4.......then 75/5= 15 answer is YES
Let z=74..... then 75/75=1 answer is YES

From S(1) and S(2) we know that the only value that makes 75/(Z+1) an integer is Z=0. So I consider C correct. Could you please help me see the flaw in my reasoning? Many thanks in advance
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Re: M00-05  [#permalink]

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New post 14 Jul 2018, 03:52
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NatalieStarr wrote:
I've spent almost one hour on this and I don't understand why the solution is not C.

From S(1)
Let x =0 ...........z=0 .........then 75/1 =75...Answer is YES
Let x =1 ...........z=75 .........then 75/76.......Answer is NO
Let x=3.....z=225...then 75/225 not integer answer is NO
And for the rest of x the answer is NO

From S(2), different
Let z=0......then 75/1=75 answer is YES
Let z=2.....then 75/3=25 answer is YES
Let z=4.......then 75/5= 15 answer is YES
Let z=74..... then 75/75=1 answer is YES

From S(1) and S(2) we know that the only value that makes 75/(Z+1) an integer is Z=0. So I consider C correct. Could you please help me see the flaw in my reasoning? Many thanks in advance


Hi NatalieStarr

In statement 2: What if you choose z = 6, will the answer be Yes too? what if z =53, Will the answer still Yes? certainly in both cases the answer is NO. You missed to test other points. You tested only the points that makes the answer yes.

So it is insufficient

Let's combine both statements

From statement 1..........z= 7x

Let's apply this in statement 2

0≤75x≤75..........x could take only 2 integer values 0 & 1.....when z= 0.............answer is yes but when z=75..........Answer is NO

Insufficient too

I hope it helps
Re: M00-05 &nbs [#permalink] 14 Jul 2018, 03:52
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