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03 Jan 2011, 10:54
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If a group of five women is participating in a 400 meter race in preparation for the Olympics, then what is the probability that either Jenny or Sally win the race?
\(1/5\)
\(14/15\)
\(2/5\)
\(1/2\)
\(3/5\)
P(j) = \(1/5\)
P(s)=\(1/4\)
p ( j or s ) = \(1/5 +1/4\) = \(9/20\)
what's going wrong
\(1/5\)
\(14/15\)
\(2/5\)
\(1/2\)
\(3/5\)
P(j) = \(1/5\)
P(s)=\(1/4\)
p ( j or s ) = \(1/5 +1/4\) = \(9/20\)
what's going wrong
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03 Jan 2011, 11:21
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1/5 + 1/5 = 2/5 ?
Since they cannot both win, (PnB) = 0, and P(AuB) = P(A)+P(B)+0
Since they cannot both win, (PnB) = 0, and P(AuB) = P(A)+P(B)+0
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
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