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# M02-09

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Math Expert
Joined: 02 Sep 2009
Posts: 52344

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15 Sep 2014, 23:17
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Difficulty:

5% (low)

Question Stats:

83% (00:35) correct 17% (09:29) wrong based on 127 sessions

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If $$x$$ is a positive number and $$2\sqrt{2}=\sqrt{\sqrt{x}-6}$$, then what is the value of $$x$$?

A. $$\frac{14}{\sqrt{2}}$$
B. $$14$$
C. $$169$$
D. $$196$$
E. $$225$$

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Math Expert
Joined: 02 Sep 2009
Posts: 52344

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15 Sep 2014, 23:17
Official Solution:

If $$x$$ is a positive number and $$2\sqrt{2}=\sqrt{\sqrt{x}-6}$$, then what is the value of $$x$$?

A. $$\frac{14}{\sqrt{2}}$$
B. $$14$$
C. $$169$$
D. $$196$$
E. $$225$$

Square both sides of the equation: $$8=\sqrt{x}-6$$;

Rearrange: $$\sqrt{x}=14$$;

Square again: $$x=196$$.

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Joined: 27 Apr 2011
Posts: 53
Location: India
GMAT Date: 06-13-2017

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26 Dec 2018, 09:54
Best Explanation Ever. Bunnel is Genius.
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Hope it's clear.
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Please +1 KUDO if my post helps. Thank you.

M02-09 &nbs [#permalink] 26 Dec 2018, 09:54
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# M02-09

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