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Bunuel
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M02-15 [#permalink] New post  15 Sep 2014, 23:17
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If \(qs \neq 0\) is \(\frac{p}{q} \gt \frac{r^2}{s}\)?


(1) \(\frac{p}{q} \gt \frac{r}{s}\)

(2) \(r = 1\)
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Bunuel
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Re M02-15 [#permalink] New post  15 Sep 2014, 23:17
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Official Solution:


(1) \(\frac{p}{q} \gt \frac{r}{s}\). If \(\frac{p}{q}=2\) and \(r=s=1\) then the answer is YES but if for example \(\frac{p}{q}=2\) and \(r=s=2\) then the answer is NO. Not sufficient.

(2) \(r = 1\). Clearly insufficient.

(1)+(2) Since from (2) \(r=1\) then the question becomes whether \(\frac{p}{q}> \frac{1}{s}\) and statement (1) directly answer this question. Sufficient.


Answer: C
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Re: M02-15 [#permalink] New post  02 Apr 2015, 06:22
C for me too.

What's OA?
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Re: M02-15 [#permalink] New post  15 Apr 2015, 01:56
Bunuel wrote:
Official Solution:


(1) \(\frac{p}{q} \gt \frac{r}{s}\). If \(\frac{p}{q}=2\) and \(r=s=1\) then the answer is YES but if for example \(\frac{p}{q}=2\) and \(r=s=2\) then the answer is NO. Not sufficient.

(2) \(r = 1\). Clearly insufficient.

(1)+(2) Since from (2) \(r=1\) then the question becomes whether \(\frac{p}{q}> \frac{1}{s}\) and statement (1) directly answer this question. Sufficient.


Answer: C


I am confused a bit here , why can't either p or q be negative? because the only condition given is qs is not equals 0. then [p][/q] will be less than [r][/s]
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Re: M02-15 [#permalink] New post  15 Apr 2015, 03:02
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Sripallavi wrote:
Bunuel wrote:
Official Solution:


(1) \(\frac{p}{q} \gt \frac{r}{s}\). If \(\frac{p}{q}=2\) and \(r=s=1\) then the answer is YES but if for example \(\frac{p}{q}=2\) and \(r=s=2\) then the answer is NO. Not sufficient.

(2) \(r = 1\). Clearly insufficient.

(1)+(2) Since from (2) \(r=1\) then the question becomes whether \(\frac{p}{q}> \frac{1}{s}\) and statement (1) directly answer this question. Sufficient.


Answer: C


I am confused a bit here , why can't either p or q be negative? because the only condition given is qs is not equals 0. then [p][/q] will be less than [r][/s]


It does not matter.

The question asks: is \(\frac{p}{q} \gt \frac{r^2}{s}\)? (2) says that \(r = 1\). So, the question basically asks whether \(\frac{p}{q} \gt \frac{1}{s}\).

(1) says that \(\frac{p}{q} \gt \frac{1}{s}\), thus giving an YES answer to the question.
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Re: M02-15 [#permalink] New post  15 Apr 2015, 21:37
Bunuel wrote:
Sripallavi wrote:
Bunuel wrote:
Official Solution:


(1) \(\frac{p}{q} \gt \frac{r}{s}\). If \(\frac{p}{q}=2\) and \(r=s=1\) then the answer is YES but if for example \(\frac{p}{q}=2\) and \(r=s=2\) then the answer is NO. Not sufficient.

(2) \(r = 1\). Clearly insufficient.

(1)+(2) Since from (2) \(r=1\) then the question becomes whether \(\frac{p}{q}> \frac{1}{s}\) and statement (1) directly answer this question. Sufficient.


Answer: C


I am confused a bit here , why can't either p or q be negative? because the only condition given is qs is not equals 0. then [p][/q] will be less than [r][/s]


It does not matter.

The question asks: is \(\frac{p}{q} \gt \frac{r^2}{s}\)? (2) says that \(r = 1\). So, the question basically asks whether \(\frac{p}{q} \gt \frac{1}{s}\).

(1) says that \(\frac{p}{q} \gt \frac{1}{s}\), thus giving an YES answer to the question.



So, basically as this is a question based on fractions we do not consider whether they are positive or negative. Is it right understanding?
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Re: M02-15 [#permalink] New post  16 Apr 2015, 03:25
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Sripallavi wrote:
So, basically as this is a question based on fractions we do not consider whether they are positive or negative. Is it right understanding?


For this particular question, we can get the answer without knowing the signs of the variables because we need to know whether one fraction is greater than another. You cannot generalize and extrapolate this to other questions involving fractions.
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Re: M02-15 [#permalink] New post  09 Apr 2016, 23:10
does it simply mean as r^2 = r therefore according to statement 1 it is greater??
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Re: M02-15 [#permalink] New post  10 Apr 2016, 03:28
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oishik2910 wrote:
does it simply mean as r^2 = r therefore according to statement 1 it is greater??


Not sure I can follow what you mean. please go through the discussion above an elaborate your question. Thank you.
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Re: M02-15 [#permalink] New post  24 Apr 2018, 16:12
3
Q and S cannot be zero IS P/Q > R^2/S ?? I simplified the stem to is PS > QR^2 ??


1) P/Q > R/S

Simplified the fraction by crossing multiply PS > QR

P=2 S=1 Q=1 R=1 then 2 > 1
Is 2 > 1 ? Yes

P= -2 S=1 Q=1 R=-3 then -2 > -3
Is -2 > 9 No

INSUFFICIENT


2) R=1
Then the question stem becomes....Is PS>Q ??

INSUFFICIENT


Taking 1 and 2 together
PS > QR and R=1
It becomes PS > Q ALWAYS YES SUFFICIENT

Thanks! :-)
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Re M02-15 [#permalink] New post  25 Oct 2019, 09:25
I think this is a poor-quality question. i believe the answer is E.
S1 p/q > r/s can be yes or no
e.g. 1/2 > 1/3 - yes
- 1/2 > -1/3 - no
not suffucient
S2 - clearly insufficient
s 1and 2 still not sufficient together
answer should be E not C.

pls. enlighten me and point out my ignorance.
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Re: M02-15 [#permalink] New post  25 Oct 2019, 09:30
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Amureabc wrote:
I think this is a poor-quality question. i believe the answer is E.
S1 p/q > r/s can be yes or no
e.g. 1/2 > 1/3 - yes
- 1/2 > -1/3 - no
not suffucient
S2 - clearly insufficient
s 1and 2 still not sufficient together
answer should be E not C.

pls. enlighten me and point out my ignorance.


How is -1/2 > -1/3 true?

-1/2 < -1/3.
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Re: M02-15 [#permalink] New post  26 Oct 2019, 06:40
Bunuel wrote:
If \(qs \neq 0\) is \(\frac{p}{q} \gt \frac{r^2}{s}\)?


(1) \(\frac{p}{q} \gt \frac{r}{s}\)

(2) \(r = 1\)


#1
\(\frac{p}{q} \gt \frac{r}{s}\)
we cannot conclsively say that \(\frac{p}{q} \gt \frac{r^2}{s}\)
as value of r is not clear
insufficient
#2
r=1 ; insufficient
as value of p,q,s not know
from 1 &2
r=1 and \(\frac{p}{q} \gt \frac{r}{s}\)
so yes \(\frac{p}{q} \gt \frac{r^2}{s}\)
IMO C
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