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Cant X=0 and the consecutive numbers be 0,1 &2. The question says X is a positive integer and hence can be 0.
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Cant X=0 and the consecutive numbers be 0,1 &2. The question says X is a positive integer and hence can be 0.

ZERO.

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check for more below threads:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.
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Bunuel
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Cant X=0 and the consecutive numbers be 0,1 &2. The question says X is a positive integer and hence can be 0.

ZERO.

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check for more below threads:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.

Hi Bunuel.

I understand that in this question they are talking about positive integers but even if x = 0 and numbers 0*1*2 = 0
and zero is divisible by any number.
So it will be sufficient.

Is this correct?
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Bunuel
tani24
Cant X=0 and the consecutive numbers be 0,1 &2. The question says X is a positive integer and hence can be 0.

ZERO.

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check for more below threads:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.

Hi Bunuel.

I understand that in this question they are talking about positive integers but even if x = 0 and numbers 0*1*2 = 0
and zero is divisible by any number.
So it will be sufficient.

Is this correct?

Yes, the product of any three consecutive integers is divisible by 3. So, even if one of the integers is 0, the product will be 0, which is divisible by 3.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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