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16 Sep 2014, 00:18
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If \(n\) is an integer, is \(\frac{n^3}{16}\) a positive integer?
(1) \(\frac{n}{4}\) is an integer
(2) \(\frac{n^2}{16}\) is an integer
(1) \(\frac{n}{4}\) is an integer
(2) \(\frac{n^2}{16}\) is an integer
16 Sep 2014, 00:18
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Official Solution:
If \(n\) is an integer, is \(\frac{n^3}{16}\) a positive integer?
Note that the question asks whether \(\frac{n^3}{16}\) is a positive integer.
(1) \(\frac{n}{4}\) is an integer
If \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
(2) \(\frac{n^2}{16}\) is an integer
Similarly, if \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
(1)+(2) And again, if \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
Answer: E
If \(n\) is an integer, is \(\frac{n^3}{16}\) a positive integer?
Note that the question asks whether \(\frac{n^3}{16}\) is a positive integer.
(1) \(\frac{n}{4}\) is an integer
If \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
(2) \(\frac{n^2}{16}\) is an integer
Similarly, if \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
(1)+(2) And again, if \(n=4\), the answer is YES. However, if \(n=0\), the answer is NO. Not sufficient.
Answer: E
General Discussion
06 Jul 2018, 08:15
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The key to getting this question right is to read carefully. Note the use of "positive" integer & the implications of its usage in statement (2) and not in statement (1) and how the squares cancel out the use in statement (2).
In general, one could get many questions right just by reading them carefully.
In general, one could get many questions right just by reading them carefully.
