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M03-33

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M03-33 [#permalink]

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  25% (medium)

Question Stats:

67% (03:10) correct 33% (00:39) wrong based on 162 sessions

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Re M03-33 [#permalink]

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(1) The average (arithmetic mean) of \(x\) and \(z\) equals to \(y\). This statement tells that \(y=\frac{x+z}{2}\): if \(x=y=z=0\) then the answer is NO but if \(x=-1\), \(y=0\) and \(z=1\) then the answer is YES. Not sufficient.

(2) \(x = -z\). Not sufficient since no info about \(y\).

(1)+(2) Examples discussed for statement (1) are still valid, so we can have both NO (\(x=y=z=0\)) and YES (\(x=-1\), \(y=0\) and \(z=1\)) answers. Not sufficient.


Answer: E
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Re: M03-33 [#permalink]

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New post 24 Jun 2015, 23:21
I think a set of 3 equally spaced numbers would also show that statement 1 is insufficient because of the property that mean = median.
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Re M03-33 [#permalink]

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New post 12 Feb 2016, 01:11
I think this is a high-quality question and I agree with explanation. i think it s 700 lv q
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Re M03-33 [#permalink]

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New post 30 Aug 2016, 05:07
I think this is a high-quality question and I agree with explanation.
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Re: M03-33 [#permalink]

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New post 09 Nov 2017, 13:43
If x,y,z are consecutive then
why can't we take x,x+1,x+2? this satisfies st.1

Please help.
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Re: M03-33 [#permalink]

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Re M03-33 [#permalink]

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New post 20 May 2018, 09:04
I think this is a high-quality question and I agree with explanation.
Re M03-33   [#permalink] 20 May 2018, 09:04
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