|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
16 Sep 2014, 00:25
Kudos
Bookmarks
A drain pipe can empty a bucket in 4 hours. On a rainy day, with the bucket full, the drain pipe manages to empty the bucket in 6 hours instead. If during the rainfall, the rain adds 3 liters of water each hour, what is the capacity of the bucket?
A. 9 liters
B. 18 liters
C. 27 liters
D. 36 liters
E. 45 liters
A. 9 liters
B. 18 liters
C. 27 liters
D. 36 liters
E. 45 liters
16 Sep 2014, 00:25
Kudos
Bookmarks
Official Solution:
A drain pipe can empty a bucket in 4 hours. On a rainy day, with the bucket full, the drain pipe manages to empty the bucket in 6 hours instead. If during the rainfall, the rain adds 3 liters of water each hour, what is the capacity of the bucket?
A. 9 liters
B. 18 liters
C. 27 liters
D. 36 liters
E. 45 liters
Let the rate of the draining pipe be \(x\) liters per hour. In this case, the capacity of the bucket can be represented as \(C = time * rate = 4x\).
On a rainy day, the net outflow is \(x - 3\) liters per hour, and it takes 6 hours to empty the bucket at this adjusted rate. Hence, the bucket's capacity (C) can also be expressed as \(C = time * rate = 6(x - 3)\).
Equating the two equations, we get: \(4x = 6(x - 3)\). Solving for \(x\), we find that \(x = 9\). Consequently, the bucket's capacity is \(C = 4x = 36\) liters.
Answer: D
A drain pipe can empty a bucket in 4 hours. On a rainy day, with the bucket full, the drain pipe manages to empty the bucket in 6 hours instead. If during the rainfall, the rain adds 3 liters of water each hour, what is the capacity of the bucket?
A. 9 liters
B. 18 liters
C. 27 liters
D. 36 liters
E. 45 liters
Let the rate of the draining pipe be \(x\) liters per hour. In this case, the capacity of the bucket can be represented as \(C = time * rate = 4x\).
On a rainy day, the net outflow is \(x - 3\) liters per hour, and it takes 6 hours to empty the bucket at this adjusted rate. Hence, the bucket's capacity (C) can also be expressed as \(C = time * rate = 6(x - 3)\).
Equating the two equations, we get: \(4x = 6(x - 3)\). Solving for \(x\), we find that \(x = 9\). Consequently, the bucket's capacity is \(C = 4x = 36\) liters.
Answer: D
10 Oct 2014, 00:04
Kudos
Bookmarks
Here's how I approached it.
Rain inflow is 3l/hr
After 6 hours it would have filled in 18l
On top of this amount, the pipe would also have to drain the contents of the already filled pool.
We know that draining a filled pool takes 4 hours.
But draining a filled pool + the 18l takes 6 hours, hence it takes 2 hours to drain 18l.
Then do a ratio comparison:
If 18l takes 2 hrs, a filled pool takes 4 hrs.
18:2 = filled pool:4
Hence, filled pool = 36l
It's also easier to just draw a diagram that would look something like this:
|__+18___| 2 hrs
| x | 4 hrs
|________|
From the diagram, it is more obvious that x is 36.
Rain inflow is 3l/hr
After 6 hours it would have filled in 18l
On top of this amount, the pipe would also have to drain the contents of the already filled pool.
We know that draining a filled pool takes 4 hours.
But draining a filled pool + the 18l takes 6 hours, hence it takes 2 hours to drain 18l.
Then do a ratio comparison:
If 18l takes 2 hrs, a filled pool takes 4 hrs.
18:2 = filled pool:4
Hence, filled pool = 36l
It's also easier to just draw a diagram that would look something like this:
|__+18___| 2 hrs
| x | 4 hrs
|________|
From the diagram, it is more obvious that x is 36.
