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M06-05

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M06-05  [#permalink]

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New post 29 Jul 2018, 09:00
Bunuel niks18 chetan2u generis pushpitkc KarishmaB EMPOWERgmatRichC GMATPrepNow

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If equation \(|x| + |y| = 5\) encloses a certain region on the graph, what is the area of that region?


It is interesting to see jump from absolute modulus to intercepts in this problem.
Do we get a hint about this approach from highlighted text ?

I believe it is very difficult to solve |x| + |y| = 5 on its own. Let me know your thoughts.
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Re: M06-05  [#permalink]

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New post 29 Jul 2018, 22:53
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adkikani wrote:
Bunuel niks18 chetan2u generis pushpitkc KarishmaB EMPOWERgmatRichC GMATPrepNow

Quote:
If equation \(|x| + |y| = 5\) encloses a certain region on the graph, what is the area of that region?


It is interesting to see jump from absolute modulus to intercepts in this problem.
Do we get a hint about this approach from highlighted text ?

I believe it is very difficult to solve |x| + |y| = 5 on its own. Let me know your thoughts.


Hi adkikani

yes the question stem gives us the approach that needs to be taken to solve such type of questions. Note the question asks "area of that region", this implies that you need to first find the "Region". As you have two variables and you need to find the region, so Co-ordinate geometry becomes your obvious approach. You are given equation so you also need to know their "intercepts". Follow Bunuel ' s solution in the first page for detailed solution.
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Re: M06-05  [#permalink]

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New post 30 Jul 2018, 04:21
adkikani wrote:
Bunuel niks18 chetan2u generis pushpitkc KarishmaB EMPOWERgmatRichC GMATPrepNow

Quote:
If equation \(|x| + |y| = 5\) encloses a certain region on the graph, what is the area of that region?


It is interesting to see jump from absolute modulus to intercepts in this problem.
Do we get a hint about this approach from highlighted text ?

I believe it is very difficult to solve |x| + |y| = 5 on its own. Let me know your thoughts.


It is a co-ordinate geometry question (keywords are graph, area of the region). Just that the equations of the lines are given in a more compact format involving absolute values.
If you know your absolute values, you know the equations you will get are x + y = 5, x - y = 5 etc depending on the signs of x and y.
Also, it is very easy to visualise these lines by putting each variable equal to 0 in turn.
x + y = 5
If x = 0, y = 5 and if y = 0, x = 5 so line will intersect the axis at (0, 5) and (5, 0) and so on.
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Re: M06-05  [#permalink]

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New post 12 Oct 2018, 00:13
Hi,

If we consider other values of x and y, say 3 and 2 would the area still be the same and would be get the same geometrical figure ?

And for all the possible values of x and y, the area would be same ?
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Re: M06-05 &nbs [#permalink] 12 Oct 2018, 00:13

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