NEW HERE? LEARN MORE
closeclose
Last visit was: 09 May 2024, 04:31 It is currently 09 May 2024, 04:31
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

M06-15

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 93119
Own Kudos [?]: 622365 [8]
Given Kudos: 81810
Send PM
CAT Tests Forum Quiz Mode
M06-15 [#permalink] New post   16 Sep 2014, 00:27
8
Bookmarks
Expert Reply
00:00
A
B
C
D
E

Difficulty:

15% (low)

Question Stats:

82% (01:22) correct 18% (01:43) wrong based on 586 sessions
Hide Show timer Statistics
If two cards are drawn without replacement from a standard 52-card deck, what is the probability that both are Jacks?

A. \(\frac{1}{13}\)


B. \(\frac{1}{17}\)


C. \(\frac{30}{221}\)


D. \(\frac{7}{221}\)


E. \(\frac{1}{221}\)
ShowHide Answer
Official Answer
E
Most Helpful Reply
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 93119
Own Kudos [?]: 622365 [6]
Given Kudos: 81810
Send PM
CAT Tests Forum Quiz Mode
Re M06-15 [#permalink] New post   16 Sep 2014, 00:27
4
Kudos
1
Bookmarks
Expert Reply
Official Solution:

If two cards are drawn without replacement from a standard 52-card deck, what is the probability that both are Jacks?

A. \(\frac{1}{13}\)


B. \(\frac{1}{17}\)


C. \(\frac{30}{221}\)


D. \(\frac{7}{221}\)


E. \(\frac{1}{221}\)


The probability of drawing a Jack on the first draw is \(\frac{4}{52}\), since there are 4 Jacks in a 52-card deck. The probability of drawing a Jack on the second draw, after one Jack has already been taken, is \(\frac{3}{51}\). The overall probability of drawing both Jacks consecutively is the product of these two probabilities:

\(\frac{4}{52}*\frac{3}{51}= \frac{1}{13} * \frac{1}{17} = \frac{1}{221}\)


Answer: E
General Discussion
User avatar
sun01
Manager
Manager
Joined: 15 May 2010
Posts: 101
Own Kudos [?]: 63 [0]
Given Kudos: 65
Location: India
Concentration: Strategy, General Management
WE:Engineering (Manufacturing)
Send PM
Reviews Badge
Re: M06-15 [#permalink] New post   03 Nov 2015, 10:37
Bunnel,

One thing, I didn't get it here, is

Why P= p1x p2?

why it can't be P = P1+P2.

I am missing some fundamentals thing. Please explain to clear my concept.
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 93119
Own Kudos [?]: 622365 [3]
Given Kudos: 81810
Send PM
CAT Tests Forum Quiz Mode
Re: M06-15 [#permalink] New post   03 Nov 2015, 13:56
1
Kudos
2
Bookmarks
Expert Reply
sun01 wrote:
Bunnel,

One thing, I didn't get it here, is

Why P= p1x p2?

why it can't be P = P1+P2.

I am missing some fundamentals thing. Please explain to clear my concept.


Principle of Multiplication
If an operation can be performed in ‘m’ ways and when it has been performed in any of these ways, a second operation that can be performed in ‘n’ ways then these two operations can be performed one after the other in ‘m*n’ ways.

Principle of Addition
If an operation can be performed in ‘m’ different ways and another operation in ‘n’ different ways then either of these two operations can be performed in ‘m+n’ ways (provided only one has to be done).

Check below post for more:
Probability Made Easy!

Theory on probability problems

Data Sufficiency Questions on Probability
Problem Solving Questions on Probability

Tough Probability Questions
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 93119
Own Kudos [?]: 622365 [0]
Given Kudos: 81810
Send PM
CAT Tests Forum Quiz Mode
Re: M06-15 [#permalink] New post   15 Oct 2023, 14:12
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
GMAT Club Bot
gmatclubot
Re: M06-15 [#permalink]
15 Oct 2023, 14:12
Moderator:
Bunuel
Math Expert
93119 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions