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16 Sep 2014, 00:27
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If \(\sqrt{3 + \sqrt{x - 1}} = 4\), what is the value of \(x\)?
A. 101
B. 122
C. 157
D. 170
E. 197
A. 101
B. 122
C. 157
D. 170
E. 197
16 Sep 2014, 00:27
Kudos
Bookmarks
Official Solution:
If \(\sqrt{3 + \sqrt{x - 1}} = 4\), what is the value of \(x\)?
A. 101
B. 122
C. 157
D. 170
E. 197
Start by squaring the given expression: \(3+\sqrt{x-1}=16\).
By rearranging, we get: \(\sqrt{x-1}=13\).
Squaring once more gives: \(x-1=169\).
Therefore, \(x=170\).
Answer: D
If \(\sqrt{3 + \sqrt{x - 1}} = 4\), what is the value of \(x\)?
A. 101
B. 122
C. 157
D. 170
E. 197
Start by squaring the given expression: \(3+\sqrt{x-1}=16\).
By rearranging, we get: \(\sqrt{x-1}=13\).
Squaring once more gives: \(x-1=169\).
Therefore, \(x=170\).
Answer: D
General Discussion
21 Oct 2023, 07:27
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
