|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
12 Dec 2009, 13:02
Kudos
Bookmarks
I am not clear why the ans choice is D.
If we can conclude from the given statement that x is even and how does the statement 1 and statement 2 help to resolve the problem?
Please explain about this problem in detail.
If we can conclude from the given statement that x is even and how does the statement 1 and statement 2 help to resolve the problem?
Please explain about this problem in detail.
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block below for better discussion and related questions.
Thank you for understanding, and happy exploring!
13 Dec 2009, 04:40
Kudos
Bookmarks
1. statement 1 is sufficient by solving it
2. y/x is not odd
if y/x is not odd then it is even
for y/x to be even any one of x,y should be even and we know that if x or y is then xy is even
so both the statements are sufficient
2. y/x is not odd
if y/x is not odd then it is even
for y/x to be even any one of x,y should be even and we know that if x or y is then xy is even
so both the statements are sufficient
13 Dec 2009, 08:06
Kudos
Bookmarks
You really don't need to solve this problem. You can answer it as D without even looking at the statements.
Simplify the equation like this: \(6(x-1) = y\)
From this equation we know that y must be even. So \(xy\) must be even, no matter what the value of x is going to be. Also remember that 0 is considered as even number, so you can simply conclude that \(xy\) is even.
Simplify the equation like this: \(6(x-1) = y\)
From this equation we know that y must be even. So \(xy\) must be even, no matter what the value of x is going to be. Also remember that 0 is considered as even number, so you can simply conclude that \(xy\) is even.
