Last visit was: 14 May 2026, 12:35 It is currently 14 May 2026, 12:35
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 14 May 2026
Posts: 110,397
Own Kudos:
Given Kudos: 106,251
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,397
Kudos: 814,865
 [13]
3
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 14 May 2026
Posts: 110,397
Own Kudos:
814,865
 [2]
Given Kudos: 106,251
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,397
Kudos: 814,865
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
HarisinghKhedar
Joined: 21 Oct 2015
Last visit: 11 Jul 2016
Posts: 37
Own Kudos:
Given Kudos: 115
GMAT 1: 620 Q47 V28
GMAT 1: 620 Q47 V28
Posts: 37
Kudos: 11
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Vergoogrev
Joined: 27 Jul 2021
Last visit: 27 May 2022
Posts: 1
Given Kudos: 12
Location: India
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
why not "0" come in this window?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 14 May 2026
Posts: 110,397
Own Kudos:
Given Kudos: 106,251
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,397
Kudos: 814,865
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Vergoogrev
why not "0" come in this window?


0 does not satisfy \(|x - 3.5| \lt 2\).

The given inequality holds true for \(1.5 \lt x \lt 5.5\) and 0 is not in this range.
User avatar
BottomJee
User avatar
Retired Moderator
Joined: 05 May 2019
Last visit: 09 Jun 2025
Posts: 993
Own Kudos:
Given Kudos: 1,008
Affiliations: GMAT Club
Location: India
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 1: 430 Q31 V19
GMAT 2: 570 Q44 V25
GMAT 3: 660 Q48 V33
GPA: 3.26
WE:Engineering (Manufacturing)
Products:
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 3: 660 Q48 V33
Posts: 993
Kudos: 1,478
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 14 May 2026
Posts: 110,397
Own Kudos:
Given Kudos: 106,251
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,397
Kudos: 814,865
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
User avatar
jeet0303
Joined: 27 Feb 2023
Last visit: 20 Nov 2024
Posts: 4
Given Kudos: 6
Posts: 4
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I am unclear on the answer,

I have taken the following equations
1) x-3.5<2 => x<5.5
2) -x-3.5<2 => -5.5<x

which leads to the following inequality
-5.5<x<5.5 , therefore x belongs to {-5,-4,...,4,5} which is 11 integers

this is obviously incorrect since |-5-3.5|<2 is not true, please could you tell me where is the logical error in this approach
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 14 May 2026
Posts: 11,237
Own Kudos:
Given Kudos: 336
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,237
Kudos: 45,184
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jeet0303
I am unclear on the answer,

I have taken the following equations
1) x-3.5<2 => x<5.5
2) -x-3.5<2 => -5.5<x

which leads to the following inequality
-5.5<x<5.5 , therefore x belongs to {-5,-4,...,4,5} which is 11 integers

this is obviously incorrect since |-5-3.5|<2 is not true, please could you tell me where is the logical error in this approach

The error is in red coloured portion. You have not multiplied -3.5 with the - sign.
-(x-3.5)<2
-x+3.5<2
x>1.5
User avatar
siya1998
Joined: 15 Nov 2020
Last visit: 22 Oct 2025
Posts: 9
Own Kudos:
Given Kudos: 32
Posts: 9
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I used the radius center method shared by Bunuel in the Absolute Values tutorial— a < x < b then |x - C| < R is valid; center : (a + b)/2 = 3.5, radius : (b - a)/2 = 2 on solving; b = 5.5, a = 1.5. Integers between 1.5 and 5.5 are 2, 3, 4, 5.
Bunuel
Official Solution:

How many integers \(x\) are there so that \(|x - 3.5| \lt 2\)?

A. 2
B. 3
C. 4
D. 5
E. 6


\(|x-3.5| \lt 2\) means that \(-2 \lt x-3.5 \lt 2\).

Now, add 3.5 to all three parts: \(1.5 \lt x \lt 5.5\).

Since given that \(x\) is an integer, then it can take the following four values: 2, 3, 4, and 5.


Answer: C
User avatar
Condemned13
Joined: 29 Nov 2015
Last visit: 25 Dec 2025
Posts: 6
Posts: 6
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I like the solution - it’s helpful.
Moderators:
Math Expert
110397 posts
Founder
43276 posts