Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
16 Sep 2014, 00:41
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
44% (01:48) correct
56%
(01:22)
wrong
based on 308
sessions
History
Date
Time
Result
Not Attempted Yet
Is the range of data set \(S\) greater than its average (arithmetic mean)?
(1) All elements in data set \(S\) are negative.
(2) The median of data set \(S\) is negative.
(1) All elements in data set \(S\) are negative.
(2) The median of data set \(S\) is negative.
16 Sep 2014, 00:41
Kudos
Bookmarks
Official Solution:
Is the range of data set \(S\) greater than its average (arithmetic mean)?
Note that the range of any set is always greater than or equal to zero.
(1) All elements in data set \(S\) are negative.
Since the mean of a set with all negative elements is also negative, it will always be less than its range (which is always non-negative). Sufficient.
(2) The median of data set \(S\) is negative.
This suggests that the data set contains at least one negative element. Let's examine two possible cases:
A. If all elements in set \(S\) are negative, then we have the same scenario as in the first statement, and therefore, \(Range \gt Mean\);
B. If not all elements in set \(S\) are negative, then since \(Range = Largest - Smallest\), the range will be greater than the largest element (since the smallest element in set \(S\) is negative). For example, consider the set {-1, -1, 2}: the range of this set is \(Range = 2 - (-1) = 3 \gt 2\). Conversely, the mean will be less than the largest element, indicating that \(Range \gt Largest \gt Mean\).
So, in any case \(Range \gt Mean\). Sufficient.
Answer: D
Is the range of data set \(S\) greater than its average (arithmetic mean)?
Note that the range of any set is always greater than or equal to zero.
(1) All elements in data set \(S\) are negative.
Since the mean of a set with all negative elements is also negative, it will always be less than its range (which is always non-negative). Sufficient.
(2) The median of data set \(S\) is negative.
This suggests that the data set contains at least one negative element. Let's examine two possible cases:
A. If all elements in set \(S\) are negative, then we have the same scenario as in the first statement, and therefore, \(Range \gt Mean\);
B. If not all elements in set \(S\) are negative, then since \(Range = Largest - Smallest\), the range will be greater than the largest element (since the smallest element in set \(S\) is negative). For example, consider the set {-1, -1, 2}: the range of this set is \(Range = 2 - (-1) = 3 \gt 2\). Conversely, the mean will be less than the largest element, indicating that \(Range \gt Largest \gt Mean\).
So, in any case \(Range \gt Mean\). Sufficient.
Answer: D
General Discussion
popov
Joined: 18 Jan 2014
Last visit: 27 Nov 2021
Posts: 160
Own Kudos:
Given Kudos: 87
Location: India
Schools: Kenan-Flagler '19 (M)
GMAT 1: 740 Q50 V40
GRE 1: Q170 V160
Products:
31 Jul 2015, 00:00
Kudos
Bookmarks
Bunuel
What if the set has only one number Set: {x}. Can we rule out this option saying that range is not defined for set consisting of one number? Or range is 0 for this set?
