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CMcAboy
Joined: 01 Mar 2009
Last visit: 10 Apr 2017
Posts: 175
Own Kudos:
Given Kudos: 23
Location: United States
Concentration: Strategy, Technology
Schools: Goizueta '16 (M$) Duke '16 (D) Tuck '16 (D) Johnson '16 (D) Darden '16 (D) Ross '16 (WL) McDonough '16 (A)
GMAT 1: 660 Q47 V34
GMAT 2: 680 Q46 V38
GPA: 3.2
WE:Consulting (Computer Software)
Schools: Goizueta '16 (M$) Duke '16 (D) Tuck '16 (D) Johnson '16 (D) Darden '16 (D) Ross '16 (WL) McDonough '16 (A)
GMAT 2: 680 Q46 V38
Posts: 175
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116
25 Jul 2011, 21:52
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What is the least integer N such that when divided by 25 or 7 it leaves remainder 1?
a) 76
b) 101
c) 126
d) 151
e) 176
The OA is E, but I disagree.
I don't think the logic is correct in this question. I interpreted the question as "If N/25 leaves a remainder of 1" OR "If N/7 leaves a remainder of 1". An "OR" operator indicates that only one condition has to pass, therefore the answer should be A.
76 / 25 = 3 with a remainder of 1
76 is the smallest digit available.
a) 76
b) 101
c) 126
d) 151
e) 176
The OA is E, but I disagree.
I don't think the logic is correct in this question. I interpreted the question as "If N/25 leaves a remainder of 1" OR "If N/7 leaves a remainder of 1". An "OR" operator indicates that only one condition has to pass, therefore the answer should be A.
76 / 25 = 3 with a remainder of 1
76 is the smallest digit available.
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27 Jul 2011, 03:10
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E is right answer
As Q ask N is the integer either you divide it by 25 or by 7 reminder should be 1
Only E satisfy this condition. Here Examiner is looking to N integer which can fulfill both conditions
Thanks
As Q ask N is the integer either you divide it by 25 or by 7 reminder should be 1
Only E satisfy this condition. Here Examiner is looking to N integer which can fulfill both conditions
Thanks
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
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