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07 Jul 2009, 06:43
Kudos
Bookmarks
If \(a\) and \(b\) are integers, is \(\frac{a}{b}\) an even integer?
1. \(ab\) is odd
2. \(a + b\) is even
Posted it but then realized I understood it
OA
BB/Moderators--Can we club all the explanations of Gmat Club Tests--M # wise
1. \(ab\) is odd
2. \(a + b\) is even
Posted it but then realized I understood it
OA
BB/Moderators--Can we club all the explanations of Gmat Club Tests--M # wise
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07 Jul 2009, 08:04
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IMO A
1. ab is odd
Implies, both a and b are odd numbers. (In case even one of them is even, the product would also be even.)
when both numbers are odd, then a/b will also be either a odd integer or a decimal number, but can never be even integer.
Hence A is sufficient to determine.
2. a+b is even
Either both a and b are odd, or both even.
We cannot conclude that a/b would be odd or even
1. ab is odd
Implies, both a and b are odd numbers. (In case even one of them is even, the product would also be even.)
when both numbers are odd, then a/b will also be either a odd integer or a decimal number, but can never be even integer.
Hence A is sufficient to determine.
2. a+b is even
Either both a and b are odd, or both even.
We cannot conclude that a/b would be odd or even
