Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Mar 2709:30 AM PDT
-10:30 AM PDT
Preparing for the GMAT? Avoid these 5 major mistakes that can lower your score and hurt your MBA dreams. In this expert panel discussion, 4 top GMAT coaches - GMAT Ninja, Jeff Miller from TTP, Rida Shafiq from eGMAT, and Chris Gentry from Manhattan Prep- Mar 27
10:00 AM PDT
-11:00 AM PDT
What happens after getting an MBA? Is it worth the investment? To find out, I interviewed 10 GMAT Club professionals who have completed their MBAs and built careers in consulting, finance, tech, and entrepreneurship. Their answers might surprise you! 
Mar 1910:00 AM EDT
-11:59 PM EDT
Get a massive $250 off the TTP OnDemand GMAT course by using the coupon code FLASH25 at checkout. If you prefer learning through engaging video lessons, TTP OnDemand GMAT is exactly what you need.- Mar 26
10:00 AM PDT
-11:00 AM PDT
Confused about how to get the most from your GMAT mock tests? In this video, learn the perfect strategy to analyze GMAT mocks effectively and boost your score. We break down the common mistakes GMAT aspirants make when using mock tests 
Mar 2911:30 AM EDT
-12:30 PM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Mar 3005:30 AM PDT
-07:30 AM PDT
We know Strengthen and Weaken questions account for more than 50% of the CR questions on the GMAT. With CR becoming even more important on GMAT Focus, it's time you strengthen your weaknesses with an approach that improves your solving time and accuracy!
Mar 3011:00 AM IST
-01:00 PM IST
Attend this session to evaluate your current skill level, learn process skills, and solve through tough Arithmetic questions.
Mar 3110:00 AM EDT
-11:59 PM EDT
The Target Test Prep team has recently introduced TTP OnDemand GMAT, a 400-hour live masterclass video course created by Scott Woodbury-Stewart, founder and CEO of Target Test Prep.
16 Sep 2014, 00:59
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
64% (02:18) correct
36%
(02:29)
wrong
based on 103
sessions
History
Date
Time
Result
Not Attempted Yet
A set consists of 19 elements with an average of \(a\). If addition of a new element increases the average by \(k\%\), what is the value of the new element?
A. \(a(1 + \frac{k}{5})\)
B. \(a*\frac{k}{100} - 20a\)
C. \(20a(1 + \frac{k}{100})\)
D. \(20(1 + \frac{k}{100}) - 19a\)
E. \(a*\frac{k}{5} - 19a\)
A. \(a(1 + \frac{k}{5})\)
B. \(a*\frac{k}{100} - 20a\)
C. \(20a(1 + \frac{k}{100})\)
D. \(20(1 + \frac{k}{100}) - 19a\)
E. \(a*\frac{k}{5} - 19a\)
16 Sep 2014, 00:59
Kudos
Bookmarks
Official Solution:
A set consists of 19 elements with an average of \(a\). If addition of a new element increases the average by \(k\%\), what is the value of the new element?
A. \(a(1 + \frac{k}{5})\)
B. \(a*\frac{k}{100} - 20a\)
C. \(20a(1 + \frac{k}{100})\)
D. \(20(1 + \frac{k}{100}) - 19a\)
E. \(a*\frac{k}{5} - 19a\)
Let \(x\) represent the value of the new element.
The new average is given by \(\frac{\text{new sum} }{20} = \frac{\text{old sum} + x}{20} = \frac{19a + x}{20}\).
Given that the average increased by \(k\%\), we'd get \(\frac{19a + x}{20} = (1 + \frac{k}{100})*a\).
\(19a + x = a*(20 + \frac{k}{5})\).
\(x = a*(20 + \frac{k}{5})-19a\).
\(x = a * (1 + \frac{k}{5})\).
Answer: A
A set consists of 19 elements with an average of \(a\). If addition of a new element increases the average by \(k\%\), what is the value of the new element?
A. \(a(1 + \frac{k}{5})\)
B. \(a*\frac{k}{100} - 20a\)
C. \(20a(1 + \frac{k}{100})\)
D. \(20(1 + \frac{k}{100}) - 19a\)
E. \(a*\frac{k}{5} - 19a\)
Let \(x\) represent the value of the new element.
The new average is given by \(\frac{\text{new sum} }{20} = \frac{\text{old sum} + x}{20} = \frac{19a + x}{20}\).
Given that the average increased by \(k\%\), we'd get \(\frac{19a + x}{20} = (1 + \frac{k}{100})*a\).
\(19a + x = a*(20 + \frac{k}{5})\).
\(x = a*(20 + \frac{k}{5})-19a\).
\(x = a * (1 + \frac{k}{5})\).
Answer: A
07 Oct 2023, 13:45
Kudos
Bookmarks
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
