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16 Sep 2014, 01:00
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An investor purchased \(n\) shares of Company A at $15 each and \(n\) shares of Company B at $20 each. If a month later, the investor sold all these shares at $20 each, earning a profit of $200, what is the value of \(n\)?
A. 35
B. 40
C. 50
D. 60
E. 75
A. 35
B. 40
C. 50
D. 60
E. 75
16 Sep 2014, 01:00
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Official Solution:
An investor purchased \(n\) shares of Company A at $15 each and \(n\) shares of Company B at $20 each. If a month later, the investor sold all these shares at $20 each, earning a profit of $200, what is the value of \(n\)?
A. 35
B. 40
C. 50
D. 60
E. 75
The investor's profit is given by \(2n * $20 - ($15n + $20n) = $200\). Simplifying this, we get \(5n = $200\), which leads to \(n = 40\).
Another perspective to consider is that the profit of $200 was generated solely from selling Company A's shares. Each of these shares contributed a profit of $20 - $15 = $5. Consequently, \(n = \frac{200}{5} = 40\).
Answer: B
An investor purchased \(n\) shares of Company A at $15 each and \(n\) shares of Company B at $20 each. If a month later, the investor sold all these shares at $20 each, earning a profit of $200, what is the value of \(n\)?
A. 35
B. 40
C. 50
D. 60
E. 75
The investor's profit is given by \(2n * $20 - ($15n + $20n) = $200\). Simplifying this, we get \(5n = $200\), which leads to \(n = 40\).
Another perspective to consider is that the profit of $200 was generated solely from selling Company A's shares. Each of these shares contributed a profit of $20 - $15 = $5. Consequently, \(n = \frac{200}{5} = 40\).
Answer: B
23 Oct 2023, 02:11
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I've revised the question and solution, incorporating additional details for improved clarity. I trust this makes it more comprehensible.
