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JackSparr0w

To solve this question,

First find the value of f(1/x). To do this, replace x with 1/x in the equation.

so f(1/x)=(1/x)/((1/x)+1) = 1/1+x

Now check which option will give you 1/1+x.

Option A : f(x) = x/x+1 not equal..

Option B : -f(x) = -x/x+1 not equal..

Option C : 1/f(x) = x+1/x not equal..

Option D : 1-f(x) = 1-(x/x+1) =(x+1-x)/x+1 = 1/x+1 .. This is the answer.

Option E : None..


+1 Kudos if this helps..
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JackSparr0w

To solve this question,

First find the value of f(1/x). To do this, replace x with 1/x in the equation.

so f(1/x)=(1/x)/((1/x)+1) = 1/1+x

Now check which option will give you 1/1+x.

Option A : f(x) = x/x+1 not equal..

Option B : -f(x) = -x/x+1 not equal..

Option C : 1/f(x) = x+1/x not equal..

Option D : 1-f(x) = 1-(x/x+1) =(x+1-x)/x+1 = 1/x+1 .. This is the answer.

Option E : None..


+1 Kudos if this helps..

Thanks! Got it!

For others, I think it may be helpful to elaborate on one other point. After you find that f(1/x) = 1/(1+x), compare this to the answer choices by substituting a value for x.

Ex: (assume x = 2). When x is 2, 1/(1+x) becomes 1/(1+2) or (1/3).

We also know f(x) = x/(x+1) from the question stem. So when x=2, f(x)=2/(2+1), or 2/3. We need to find the answer choice that changes 2/3 to 1/3.

Knowing this we can see that choice D is correct. Choice D is 1-f(x), or 1-(2/3) which equals 1/3; the same as our answer above.
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I have reached the substitution but unable to get the process after that...
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Tanyanagra
I have reached the substitution but unable to get the process after that...

Hi Tanyanagra,

For me using substitution is better than trying to manipulate the variables, especially under pressure....here's how I solve it !

Substitute x=2 into this 1st equation: f(x) = x divided by x+1 f(2) = 2 divided by 2+1 = 2/3

Then, the question asks what is f(1/x) in terms of f(x)?

You'll need to convert the f(x) to f(1/x) that will be 1/x divided by 1/x+1

Substitute x=2 into this 2nd equation f(1/x): 1/2 divided by 1/2+1 = 1/2 divided by 3/2 = 1/2 * 2/3 = 1/3

Now, you have to find 1/3in the answer choices:

A) f(x) = 2/3 not a match

B) - f(x) = - 2/3 not a match

C) 1/f(x) = 1 divided by 2/3 = 3/2 not a match

D) 1 - f(x) = 1 - 2/3 = 1/3 BINGO!! That's a match

E) none of the above = wrong

I hope it helps!

Thanks Ale! :-)
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Official Solution:

If \(f(x) = \frac{x}{x + 1}\), what is \(f(\frac{1}{x})\) in terms of \(f(x)\)?

A. \(f(x)\)
B. \(-f(x)\)
C. \(\frac{1}{f(x)}\)
D. \(1 - f(x)\)
E. none of the above


\(f(\frac{1}{x})= \frac{\frac{1}{x} }{\frac{1}{x} + 1} =\)

\(= \frac{\frac{1}{x} }{(\frac{1+x}{x})} =\)

\(=\frac{1}{x} *\frac{x}{x+1} =\)

\(=\frac{1}{1 + x} =\)

\(=\frac{(1 + x) - x}{1 + x} =\)

\(=\frac{1 + x}{1 + x}-\frac{x}{1+x}=\)

\(=1 - \frac{x}{1 + x} =\)

\(=1 - f(x)\)


Answer: D

------------------

Hi Bunuel,
It's not given to us that 'x' is not equal to 0 so how can we cancel 'x' when solving for f(1/x)??
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Bunuel
Official Solution:

If \(f(x) = \frac{x}{x + 1}\), what is \(f(\frac{1}{x})\) in terms of \(f(x)\)?

A. \(f(x)\)
B. \(-f(x)\)
C. \(\frac{1}{f(x)}\)
D. \(1 - f(x)\)
E. none of the above


\(f(\frac{1}{x})= \frac{\frac{1}{x} }{\frac{1}{x} + 1} =\)

\(= \frac{\frac{1}{x} }{(\frac{1+x}{x})} =\)

\(=\frac{1}{x} *\frac{x}{x+1} =\)

\(=\frac{1}{1 + x} =\)

\(=\frac{(1 + x) - x}{1 + x} =\)

\(=\frac{1 + x}{1 + x}-\frac{x}{1+x}=\)

\(=1 - \frac{x}{1 + x} =\)

\(=1 - f(x)\)


Answer: D

------------------

Hi Bunuel,
It's not given to us that 'x' is not equal to 0 so how can we cancel 'x' when solving for f(1/x)??

If x were 0, 1/x would be undefined and f(1/x) wouldn't make any sense.
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hi Bunuel

after solving f(1/x)= 1/1+x, i multiplied and divide the R.H.S with x and got x/x(1+x) or 1/x *F(x), why is it wrong??
Bunuel
Official Solution:

If \(f(x) = \frac{x}{x + 1}\), what is \(f(\frac{1}{x})\) in terms of \(f(x)\)?

A. \(f(x)\)
B. \(-f(x)\)
C. \(\frac{1}{f(x)}\)
D. \(1 - f(x)\)
E. none of the above


\(f(\frac{1}{x})= \frac{\frac{1}{x} }{\frac{1}{x} + 1} =\)

\(= \frac{\frac{1}{x} }{(\frac{1+x}{x})} =\)

\(=\frac{1}{x} *\frac{x}{x+1} =\)

\(=\frac{1}{1 + x} =\)

\(=\frac{(1 + x) - x}{1 + x} =\)

\(=\frac{1 + x}{1 + x}-\frac{x}{1+x}=\)

\(=1 - \frac{x}{1 + x} =\)

\(=1 - f(x)\)


Answer: D
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shaliny
hi Bunuel

after solving f(1/x)= 1/1+x, i multiplied and divide the R.H.S with x and got x/x(1+x) or 1/x *F(x), why is it wrong??


You went wrong for two reasons.

First, (1/x)*f(x) is not even among the answer choices.

Second, the question specifically asks to express f(1/x) in terms of f(x), but your expression still has both f(x) and x in it. That’s why it’s not valid.
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There was an option E- None , that's why i thought my calculation could be right:?
according to second reason, i can't write as F(1/x) = f(x)/x, isn't? i mean this representation is not in option here but generally, is wrong or right as you said 1/x and f(x) both present .
Bunuel


You went wrong for two reasons.

First, (1/x)*f(x) is not even among the answer choices.

Second, the question specifically asks to express f(1/x) in terms of f(x), but your expression still has both f(x) and x in it. That’s why it’s not valid.
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shaliny
There was an option E- None , that's why i thought my calculation could be right:?
according to second reason, i can't write as F(1/x) = f(x)/x, isn't? i mean this representation is not in option here but generally, is wrong or right as you said 1/x and f(x) both present .


1. Your algebraic manipulations are correct.
2. In terms of f(x) means there should be only f(x).
3. Modified option E.
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