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# M20-16

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Math Expert
Joined: 02 Sep 2009
Posts: 49320

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16 Sep 2014, 01:08
00:00

Difficulty:

5% (low)

Question Stats:

93% (00:46) correct 7% (01:12) wrong based on 121 sessions

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Medicine A is 25 percent more expensive than medicine B. Medicine B is 20 percent cheaper than medicine C. If medicine C costs $10, what is the difference between the price of medicine A and the price of medicine B ? A.$1.25
B. $1.50 C.$2.00
D. $2.50 E.$2.75

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Math Expert
Joined: 02 Sep 2009
Posts: 49320

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16 Sep 2014, 01:08
Official Solution:

Medicine A is 25 percent more expensive than medicine B. Medicine B is 20 percent cheaper than medicine C. If medicine C costs $10, what is the difference between the price of medicine A and the price of medicine B ? A.$1.25
B. $1.50 C.$2.00
D. $2.50 E.$2.75

Let $$A$$, $$B$$, and $$C$$ denote the prices of the respective medicine. We know that $$A = 1.25B$$ and that $$B = 0.8C$$. Because $$C = 10$$, $$B = 0.8*10 = 8$$ and $$A = 1.25B = 1.25*8 = 10$$. The difference between the price of medicine A and the price of medicine B $$= 10 - 8 = 2$$.

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Joined: 08 Jun 2015
Posts: 503
Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
GPA: 3.33

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04 Oct 2017, 05:42
+1 for C.
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" The few , the fearless "

Intern
Joined: 04 Oct 2017
Posts: 1

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04 Oct 2017, 08:06
A/B=125/100
SO A/B=5/4
AND
B/C=80/100
SO B/C=4/5
THAT MEANS
A:B:C=5:4:5
ACCORDING TO QUESTION
5 PART=10
1 PART=2

SO THAT
A=10 AND B=8
AND DIFFERENCE IS 10-8=2
ANS = 2
OPTION = C
Re: M20-16 &nbs [#permalink] 04 Oct 2017, 08:06
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# M20-16

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