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M21-22

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M21-22  [#permalink]

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New post 16 Sep 2014, 01:11
1
2
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

56% (01:28) correct 44% (01:34) wrong based on 122 sessions

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Re M21-22  [#permalink]

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New post 16 Sep 2014, 01:11
Official Solution:


If \(a\), \(b\), and \(c\) are consecutive integers, which of the following can be true?

I. \(abc\) is divisible by 6

II. \(a + c - b\) is odd

III. \(\frac{c}{a} \gt b\)


A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III

All the three scenarios are possible. Consider \(a = -8\), \(b = -7\), \(c = -6\). Note that the question asks "what 'can' be true" rather than "what 'must' be true".

Answer: E
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Re: M21-22  [#permalink]

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New post 10 Sep 2016, 16:19
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Can be true and Must be true makes all the difference here.
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Re: M21-22  [#permalink]

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New post 29 Mar 2017, 13:19
I should have looked at it more closely.....shouldnt be missing these type of problems because of language.
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M21-22  [#permalink]

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New post 25 Nov 2017, 08:12
Hi,

Can't we take -1, 0 & +1 ----> the answers in this case might be different ?

Also, if you could explain the difference b/w "must be true" & "can be true", I think i am missing a point here.

Thx
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Re: M21-22  [#permalink]

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New post 25 Nov 2017, 08:15
quest800 wrote:
Hi,

Can't we take -1, 0 & +1 ----> the answers in this case might be different ?

Also, if you could explain the difference b/w "must be true" & "can be true", I think i am missing a point here.

Thx


Look at the highlighted part of the solution:
All the three scenarios are possible. Consider \(a = -8\), \(b = -7\), \(c = -6\). Note that the question asks "what 'can' be true" rather than "what 'must' be true".
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Re: M21-22  [#permalink]

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New post 13 Aug 2018, 00:43
I understand the difference between 'can be' true and 'must be' true here. Were this question to come in the exam, I would basically need to test multiple consecutive number options till I get an option i.e (-8, -7, -6) that satisfies all three? (-8, -7, -6) this combination is rather unusual to test as the first thing that comes to one's mind. Is there a shorter way to address this?
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Re: M21-22  [#permalink]

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New post 08 Dec 2018, 20:14
Bunuel wrote:
Official Solution:


If \(a\), \(b\), and \(c\) are consecutive integers, which of the following can be true?

I. \(abc\) is divisible by 6

II. \(a + c - b\) is odd

III. \(\frac{c}{a} \gt b\)


A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III

All the three scenarios are possible. Consider \(a = -8\), \(b = -7\), \(c = -6\). Note that the question asks "what 'can' be true" rather than "what 'must' be true".

Answer: E



hi Bunel,

If it is given in the question that a,b,c, are consecutive numbers, then we can by default assume that the order is a<b<c ??
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Re: M21-22  [#permalink]

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New post 09 Dec 2018, 00:11
kanthaliya wrote:
Bunuel wrote:
Official Solution:


If \(a\), \(b\), and \(c\) are consecutive integers, which of the following can be true?

I. \(abc\) is divisible by 6

II. \(a + c - b\) is odd

III. \(\frac{c}{a} \gt b\)


A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III

All the three scenarios are possible. Consider \(a = -8\), \(b = -7\), \(c = -6\). Note that the question asks "what 'can' be true" rather than "what 'must' be true".

Answer: E



hi Bunel,

If it is given in the question that a,b,c, are consecutive numbers, then we can by default assume that the order is a<b<c ??


No. On the GMAT a, b, c are consecutive integers does not necessarily mean that a < b < c.
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M21-22  [#permalink]

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New post 24 Sep 2019, 11:01
I tried with a very different approach.
Tough, I was a victim of Must Be true or Can be true trap, have a look at my approach.
Refer to snapshot by Aadi01 in forum discussion link
Hit Kudos and let me know you find this helpful...
>> !!!

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M21-22   [#permalink] 24 Sep 2019, 11:01
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