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Re: M22-09 [#permalink]
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ncplagge wrote:
Hi --

How come we wouldn't need to know how many students were in each of the city's schools and get a weighted average? Is it because the average is the same across all the schools?

Thanks!


Yes. If the average is the same for several groups then the overall average would be the average of any of the groups. For example, if the average age of group A is 12 years and the average age of group B is also 12 years, then the overall average age will also be 12 years irrespective of the number of people in the groups. Or using the formula: \(\frac{12N_1 + ... + 12N_k}{N_1 + ... + N_k} = \frac{12(N_1 + ... + N_k)}{N_1 + ... + N_k}=12\) (notice that N1, N2, ..., Nk are the number of students in the schools and all of them are reduced).
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Re: M22-09 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M22-09 [#permalink]
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