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2 laptops and 6 desktops were bought for office needs. If a laptop is twice as expensive as a desktop, what percent of the money was spent on laptops?

A. 30 B. 40 C. 48 D. 50 E. 60

Let \(x\) denote the price of a desktop. The money spent \(= 2(2x) + 6x = 10x\). The money spent on laptops \(= 2(2x) = 4x\). The answer is \(\frac{4x}{10x}*100\% = 40\%\).

Let T be the total money spent on buying 2 laptops (L) and 6 desktops (D) then , 2L + 6D = T Also, given L = 2D => 2L + 6 (L/2) = T => L = T/5 which implies to 20% of the total money spent. Since, 2 laptops were bought so total percentage of money spent = 2* 20% = 40% (option no. B)

I used Test IT method: (we are looking for the ratio of $ spent on Laptops to all $ spent on all 8 devices) 1) since L = 2D, we'll let "L" be $4 and "D" be $2. 2) and since we have 2 L's and 6 D's, we'll get the total spending: 2(4) + 6(2) = $20 total cost 3) notice from previous step that 2 L's cost $8, and that total is $20, hence we have 8/20, or 40/100 ---> 40%