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16 Sep 2014, 01:18
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16 Sep 2014, 01:18
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Official Solution:
What is the units digit of \(3^{987}\)?
A. 1
B. 3
C. 6
D. 7
E. 9
The units digit of \(3^1\) is 3;
The units digit of \(3^2\) is 9;
The units digit of \(3^3\) is 7;
The units digit of \(3^4\) is 1;
The units digit of \(3^5\) is 3 AGAIN;
...
As observed, the units digit of 3 raised to a positive integer power follows a repeating pattern of four: {3, 9, 7, 1}. Therefore, the units digit of \(3^{987}\) (since \(987 = 4n + 3\), a multiple of 4 plus 3) is the same as the units digit of \(3^3\), which is 7.
Answer: D
What is the units digit of \(3^{987}\)?
A. 1
B. 3
C. 6
D. 7
E. 9
The units digit of \(3^1\) is 3;
The units digit of \(3^2\) is 9;
The units digit of \(3^3\) is 7;
The units digit of \(3^4\) is 1;
The units digit of \(3^5\) is 3 AGAIN;
...
As observed, the units digit of 3 raised to a positive integer power follows a repeating pattern of four: {3, 9, 7, 1}. Therefore, the units digit of \(3^{987}\) (since \(987 = 4n + 3\), a multiple of 4 plus 3) is the same as the units digit of \(3^3\), which is 7.
Answer: D
13 Feb 2018, 09:21
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The unit digits of multiples of 3 happens in a cycle of (3, 9, 7, 1)
By this we can find unit digits of 3^987 is 7.
Ans : D
Posted from my mobile device
Posted from my mobile device
By this we can find unit digits of 3^987 is 7.
Ans : D
Posted from my mobile device
Posted from my mobile device
