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16 Sep 2014, 01:22
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\(\frac{2}{3}* \sqrt{ \frac{ 0.5 - \frac{1}{3} }{6} } = ?\)
A. \(\frac{1}{9}\)
B. \(\frac{1}{6}\)
C. \(\frac{2}{3}\)
D. 4
E. 6
A. \(\frac{1}{9}\)
B. \(\frac{1}{6}\)
C. \(\frac{2}{3}\)
D. 4
E. 6
16 Sep 2014, 01:22
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Official Solution:
\(\frac{2}{3}* \sqrt{ \frac{ 0.5 - \frac{1}{3} }{6} } = ?\)
A. \(\frac{1}{9}\)
B. \(\frac{1}{6}\)
C. \(\frac{2}{3}\)
D. 4
E. 6
\(\frac{2}{3}*\sqrt{ \frac{ 0.5 - \frac{1}{3} }{6} } =\)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{1}{2} - \frac{1}{3} }{6} }= \)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{3}{6} - \frac{2}{6} }{6} }= \)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{1}{6} }{6} }=\)
\(=\frac{2}{3}* \sqrt{ \frac{1}{36} } =\)
\(=\frac{2}{3}*\frac{1}{6} =\)
\(=\frac{1}{9}\).
Answer: A
\(\frac{2}{3}* \sqrt{ \frac{ 0.5 - \frac{1}{3} }{6} } = ?\)
A. \(\frac{1}{9}\)
B. \(\frac{1}{6}\)
C. \(\frac{2}{3}\)
D. 4
E. 6
\(\frac{2}{3}*\sqrt{ \frac{ 0.5 - \frac{1}{3} }{6} } =\)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{1}{2} - \frac{1}{3} }{6} }= \)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{3}{6} - \frac{2}{6} }{6} }= \)
\(=\frac{2}{3}*\sqrt{ \frac{ \frac{1}{6} }{6} }=\)
\(=\frac{2}{3}* \sqrt{ \frac{1}{36} } =\)
\(=\frac{2}{3}*\frac{1}{6} =\)
\(=\frac{1}{9}\).
Answer: A
06 May 2023, 16:19
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
