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18 Jan 2010, 19:54
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Please explain, how to solve this problem...
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19 Jan 2010, 03:43
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mirzohidjon
taking different values for x
let x = -2 then we have -2/ |-2| = -1 < -2. NO
let x = -1 then we have -1/ |-1| = -1 < -1. NO
Let x = 0 then we have 0/|0| = 0<0. NO
Let x= 1 then we have 1/|1| = 1< 1. NO
let x = -1/3 then we have (-1/3)/ |(-1/3)| = -1 < (-1/3) YES
let x = 1/2 then we have (1/2)/|(1/2)| = 1 < 1/2 NO
let x = 2 then we have 2/|2| = 1 < 2 YES
so answer b expresses this correctly.
19 Jan 2010, 08:17
Kudos
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x/|x|<x =sgn(x)<x (sgn is signum function)
=>x/|x|<x ={ 1<x; x>=0 OR -1<x ; x<0 }
=> x>1 OR -1<x<0
So, B is right.
=>x/|x|<x ={ 1<x; x>=0 OR -1<x ; x<0 }
=> x>1 OR -1<x<0
So, B is right.
