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but in this case statement A contradicts to statement B. A states that x is an integer and B states that it is not.

Not so, taken together x can be zero which is an integer.
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Bunuel
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but in this case statement A contradicts to statement B. A states that x is an integer and B states that it is not.

Not so, taken together x can be zero which is an integer.

If we need to indicate that x is an integer, shouldn't the answer be C?

Statement 1 alone: Insufficient.
Statement 2 alone:
-1<x<1
|-1-6| = 7. True.
However.
|1-6| = 5. False 5 is not larger than 5. Also insufficient.

Both statement together:
If say we take zero as an integer we need statement 1 to indicate that x is in fact an integer.

|0-6| = 6. True

Sufficient.
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leochanGmat
Bunuel
Tati
but in this case statement A contradicts to statement B. A states that x is an integer and B states that it is not.

Not so, taken together x can be zero which is an integer.

If we need to indicate that x is an integer, shouldn't the answer be C?

Statement 1 alone: Insufficient.
Statement 2 alone:
-1<x<1
|-1-6| = 7. True.
However.
|1-6| = 5. False 5 is not larger than 5. Also insufficient.

Both statement together:
If say we take zero as an integer we need statement 1 to indicate that x is in fact an integer.

|0-6| = 6. True

Sufficient.

No, when considering the second statement we don't need to know that x is an integer. The question asks: "is x<1 or x>11?" and (2) says that -1<x<1, so we can answer YES to the question. In your examples you can not consider x=-1 and x=1 since in the given range (-1<x<1) -1 and 1 are not inclusive.

Hope it's clear.
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Thank you for the clarification.

Say if statement 2 is larger than 11, but not smaller than 1. The statement will still be sufficient?

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